英文:
Beego how to access params submitted with multipart/form-data header?
问题
我遇到了以下问题:
当我向我的beego
应用程序发出curl
请求时,
curl http://localhost:8080/controller/path -X POST -H 'Content-Type: multipart/form-data; charset=UTF-8' -F "file=@file.csv;filename=file.csv" -F "name=first"
我想从我的控制器中访问name
参数,但是当我尝试
func (c *Controller) Path() {
...
var name string
c.Ctx.Input.Bind(&name, "name")
// 或者我尝试 'name := c.GetString("name")'
...
}
结果始终是一个空字符串作为name
变量。
我做错了什么?在这种情况下,我如何访问参数?请给出任何建议!
更新1
我尝试了Parse to struct
方法,但没有成功...
type DataParams struct {
Name string `form:"name"`
}
cLDP := DataParams{}
if err := c.ParseForm(&cLDP); err != nil {
return ret, err
}
更新2
根据评论,我尝试了以下方法
c.Ctx.Input.ParseFormOrMulitForm(99999)
var name string
c.Ctx.Input.Bind(&name, "name")
更新3
尝试了所有方法后,我迷失了...
name := c.Ctx.Input.Query("name")
params := c.Ctx.Input.Params()
name2 := c.GetString("name")
c.Ctx.Input.ParseFormOrMulitForm(99999)
params2 := c.Ctx.Input.Params()
fmt.Println("Debug 2->", name)
fmt.Println("Debug 5->", name2)
fmt.Println("Debug 3->", params)
fmt.Println("Debug 4->", params2)
输出结果为
Debug 2->
Debug 3-> map[...]
Debug 4-> map[...]
Debug 5->
未检测到name参数
更新4
如果我使用c.Ctx.Input.RequestBody
,不出所料,它是空的。
仍然没有成功
英文:
I've ran into a problem as follows:
When I make a curl
request to my beego
app
> curl http://localhost:8080/controller/path -X POST -H 'Content-Type: multipart/form-data; charset=UTF-8' -F “file=@file.csv;filename=file.csv” -F “name=first”
I want to access name
param from my controller, but when I try
> func (c *Controller) Path() {
> ...
> var name string
> c.Ctx.Input.Bind(&name, "name")
> // or I've tried 'name := c.GetString("name")'
> ...
>}
result is always an empty string as name
variable.
What am I doing wrong ? How can I access params in this case ? Please any advice welcome !
Update 1
I've tried Parse to struct
approach, with no luck...
type DataParams struct {
Name string `form:"name"`
}
cLDP := DataParams{}
if err := c.ParseForm(&cLDP); err != nil {
return ret, err
}
Update 2
as of comment, I've tried
c.Ctx.Input.ParseFormOrMulitForm(99999)
var name string
c.Ctx.Input.Bind(&name, "name")
Update 3
after trying altogether I'm lost...
name := c.Ctx.Input.Query("name")
params := c.Ctx.Input.Params()
name2 := c.GetString("name")
c.Ctx.Input.ParseFormOrMulitForm(99999)
params2 := c.Ctx.Input.Params()
fmt.Println("Debug 2->", name)
fmt.Println("Debug 5->", name2)
fmt.Println("Debug 3->", params)
fmt.Println("Debug 4->", params2)
output is
Debug 2->
Debug 3-> map[...]
Debug 4-> map[...]
Debug 5->
no name param detected
Update 4
if I use c.Ctx.Input.RequestBody
it not surprisingly is empty
And still no luck
答案1
得分: 1
将"Content-Type: multipart/form-data"更改为"enctype:multipart/form-data"。
英文:
change the "Content-Type: multipart/form-data to enctype:multipart/form-data
答案2
得分: 0
你可以使用Query方法来访问name
参数的值,像这样:
name := c.Ctx.Input.Query("name")
如果你想使用Bind
方法,可以这样做:
names := []string{}
if err := c.Ctx.Input.Bind(&names, "name"); err != nil {
panic(err)
}
log.Println(name[0]) // first
但是你还需要更新你的curl
命令,明确将name
参数声明为一个带有索引的数组:
curl ... -F "name[0]=first"
这是因为Go在内部将表单参数值存储在字符串切片中(参见url.Values),beego也是使用这种方式,所以在beego解析表单后,它会变成url.Values{"name": []string{"first"}}
,因此beego无法将[]string{"first"}
绑定到普通的string
类型中。
英文:
You should be able to access the name
parameter value using the Query method, like so:
name := c.Ctx.Input.Query("name")
If you want to use Bind
you can do something like this:
names := []string{}
if err := c.Ctx.Input.Bind(&names, "name"); err != nil {
panic(err)
}
log.Println(name[0]) // first
But you'll also have to update your curl
to specifically declare the name
parameter as an array with index:
curl ... -F "name[0]=first"
This is because internally Go stores a form's parameter values in a slice of strings (see url.Values) and beego is using this as well, so after beego parses the form it will look like this url.Values{"name": []string{"first"}}
and so beego does not know how to bind []string{"first"}
into a plain string
.
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