将结构体转换为字符串切片？

huangapple
go评论118阅读模式
英文:

Convert struct to slice of strings?

问题

我正在尝试使用encoding/csv包来编写CSV文件。我想要按行写入的所有数据都保存在以下结构体中：

  1. type record struct {
  2.     Field0 string
  3.     Field1 string
  4.     Field2 string
  5.     Field3 string
  6. }

csv包有一个名为Write的方法，它需要一个字符串切片作为参数。

是否可以将结构体转换为字符串切片？

英文:

I'm trying to write a CSV file using the package encoding/csv. All data I want to write per line is saved in a struct like this:

  1. type record struct {
  2.     Field0 string
  3.     Field1 string
  4.     Field2 string
  5.     Field3 string
  6. }

The csv package has a method called Write that requires a slice of strings.

Is it possible to convert a struct to a slice of strings?

答案1

得分: 3

例如，

  1. package main
  3. import (
  4.     "fmt"
  5. )
  7. type record struct {
  8.     Field0 string
  9.     Field1 string
  10.     Field2 string
  11.     Field3 string
  12. }
  14. func main() {
  15.     r := record{"f0", "f1", "f2", "f3"}
  16.     fmt.Printf("%q\n", r)
  17.     s := []string{
  18.         r.Field0,
  19.         r.Field1,
  20.         r.Field2,
  21.         r.Field3,
  22.     }
  23.     fmt.Printf("%q\n", s)
  24. }

输出：

  1. {"f0" "f1" "f2" "f3"}
  2. ["f0" "f1" "f2" "f3"]
英文:

For example,

  1. package main
  3. import (
  4. 	"fmt"
  5. )
  7. type record struct {
  8. 	Field0 string
  9. 	Field1 string
  10. 	Field2 string
  11. 	Field3 string
  12. }
  14. func main() {
  15. 	r := record{"f0", "f1", "f2", "f3"}
  16. 	fmt.Printf("%q\n", r)
  17. 	s := []string{
  18. 		r.Field0,
  19. 		r.Field1,
  20. 		r.Field2,
  21. 		r.Field3,
  22. 	}
  23. 	fmt.Printf("%q\n", s)
  24. }

Output:

  1. {"f0" "f1" "f2" "f3"}
  2. ["f0" "f1" "f2" "f3"]

答案2

得分: 3

我发现https://github.com/fatih/structs包非常有用...

  1. package main
  3. import (
  4.     "fmt"
  5.     "github.com/fatih/structs"
  6. )
  8. type record struct {
  9.     Field0 string
  10.     Field1 string
  11.     Field2 string
  12.     Field3 string
  13. }
  15. func main() {
  16.     r := record{"f0", "f1", "f2", "f3"}
  17.     fmt.Printf("%q\n", r)
  18.     vals := structs.Values(r)
  19.     fmt.Printf("%q\n", vals)
  20. }
  21. 输出:
  23. {"f0" "f1" "f2" "f3"}
  24. ["f0" "f1" "f2" "f3"]
英文:

I find the https://github.com/fatih/structs package to be quite useful...

  1. package main
  3. import (
  4.     "fmt"
  5.     "github.com/fatih/structs"
  6. )
  8. type record struct {
  9.     Field0 string
  10.     Field1 string
  11.     Field2 string
  12.     Field3 string
  13. }
  15. func main() {
  16.     r := record{"f0", "f1", "f2", "f3"}
  17.     fmt.Printf("%q\n", r)
  18.     vals := structs.Values(r)
  19.     fmt.Printf("%q\n", vals)
  20. }
  21. Output:
  23. {"f0" "f1" "f2" "f3"}
  24. ["f0" "f1" "f2" "f3"]

huangapple
  • 本文由 发表于 2017年4月9日 08:58:39
  • 转载请务必保留本文链接：https://go.coder-hub.com/43301956.html
  • csv
  • go
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定