英文:
How to parse array json in Go?
问题
我有以下的JSON数据：
[
{
"id": "bitcoin",
"name": "Bitcoin",
"symbol": "BTC",
"rank": "1",
"price_usd": "960.094",
"price_btc": "1.0",
"24h_volume_usd": "438149000.0",
"market_cap_usd": "15587054083.0",
"available_supply": "16234925.0",
"total_supply": "16234925.0",
"percent_change_1h": "-0.76",
"percent_change_24h": "-7.78",
"percent_change_7d": "-14.39",
"last_updated": "1490393946"
}
]
我有两个结构体：
type Valute struct {
Id string `json:"id"`
Name string `json:"name"`
Symbol string `json:"symbol"`
}
type Currency struct {
Result []Valute `json:""`
}
我想解析这个调用返回的数组：
resp, err := http.Get("https://api.coinmarketcap.com/v1/ticker/?limit=1")
defer resp.Body.Close()
v := Currency{}
body, err := ioutil.ReadAll(resp.Body)
json.Unmarshal(body, &v)
但是对我来说不起作用。Currency 是空的。
它可以用一个数组来工作：
var valutes []Valute
json.Unmarshal(body, &valutes)
但是我想使用一个结构体。
英文:
I have the following JSON data:
[
{
"id": "bitcoin",
"name": "Bitcoin",
"symbol": "BTC",
"rank": "1",
"price_usd": "960.094",
"price_btc": "1.0",
"24h_volume_usd": "438149000.0",
"market_cap_usd": "15587054083.0",
"available_supply": "16234925.0",
"total_supply": "16234925.0",
"percent_change_1h": "-0.76",
"percent_change_24h": "-7.78",
"percent_change_7d": "-14.39",
"last_updated": "1490393946"
}
]
And I have two struct:
type Valute struct {
Id string `json:"id"`
Name string `json:"name"`
Symbol string `json:"symbol"`
}
type Currency struct {
Result []Valute
}
I want to parse the array returned by this call:
resp, err := http.Get("https://api.coinmarketcap.com/v1/ticker/?limit=1")
defer resp.Body.Close()
v := Currency{}
body, err := ioutil.ReadAll(resp.Body)
json.Unmarshal(body, &v)
But it does not work for me. Currency is empty.
It works with an array:
var valutes []Valute
json.Unmarshal(body, &valutes)
But I want to use a struct.
答案1
得分: 3
你的Currency结构体只需要实现json.Unmarshaler接口。
func (c *Currency) UnmarshalJSON(b []byte) error {
return json.Unmarshal(b, &c.Result)
}
英文:
Your Currency struct simply has to implement the json.Unmarshaler interface.
func (c *Currency) UnmarshalJSON(b []byte) error {
return json.Unmarshal(b, &c.Result)
}
答案2
得分: 2
你也可以直接改成 json.Unmarshal(body, &v.Result)。
英文:
You can also just change to json.Unmarshal(body, &v.Result)
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