英文:
How to randomly split a map in Go as evenly as possible?
问题
我有一个快速的问题。我对golang还比较新手。假设我有一个如下的map：
map[int]string
如何将它随机分成两个尽可能均匀的map或数组？例如，如果有15个项，它将被分成7-8。
英文:
I have a quick question. I am fairly new to golang. Say I have a map like so:
map[int]string
How could I randomly split it into two maps or arrays and as close to even as possible? So for example, if there are 15 items, it would be split 7 - 8.
答案1
得分: 2
例如：
func split(m map[int]string) (odds map[int]string, evens map[int]string) {
n := 1
odds = make(map[int]string)
evens = make(map[int]string)
for key, value := range m {
if n % 2 == 0 {
evens[key] = value
} else {
odds[key] = value
}
n++
}
return odds, evens
}
这实际上是一个有趣的例子，因为它展示了一些对初学者来说不太明显的Go语言特性：
range m以随机顺序迭代，与我所知的其他任何语言都不同，- 取模运算符
%返回整数除法的余数， - 一个函数可以返回多个值。
英文:
For example:
func split(m map[int]string) (odds map[int]string, evens map[int]string) {
n := 1
odds = make(map[int]string)
evens = make(map[int]string)
for key, value := range m {
if n % 2 == 0 {
evens[key] = value
} else {
odds[key] = value
}
n++
}
return odds, evens
}
It is actually an interesting example, because it shows a few aspects of Go that are not obvious for beginners:
range miterates in a random order, unlike in any other language as far as I know,- the modulo operator
%returns the remainder of the integer division, - a function can return several values.
答案2
得分: 2
你可以这样做：
myStrings := make(map[int]string)
// 将值添加到myStrings中
myStrings2 := make(map[int]string)
// 为随机数种子系统时间
rand.Seed(time.Now().UTC().UnixNano())
for k, v := range myStrings {
if rand.Float32() < 0.5 {
myStrings2[k] = v
delete(myStrings, k)
}
}
https://play.golang.org/p/6OnH1k4FMu
英文:
You could do something like this:
myStrings := make(map[int]string)
// Values are added to myStrings
myStrings2 := make(map[int]string)
// Seed system time for random numbers
rand.Seed(time.Now().UTC().UnixNano())
for k, v := range myStrings {
if rand.Float32() < 0.5 {
myStrings2[k] = v
delete(myStrings, k)
}
}
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