在golang中,time.parse函数中的小时超出范围了。

huangapple go评论95阅读模式
英文:

Hour out of range on time.parse in golang

问题

我正在尝试在Go语言中解析一个日期时间字符串。我将确切的字符串作为格式传递,并得到一个解析时间错误:"01/31/2000 12:59 AM":小时超出范围。
我从输入中获取该字符串。如何使其工作?

以下是代码(https://play.golang.org/p/Kg9KfFpU2z):

func main() {
    layout := "01/31/2000 12:59 AM"
    if t, err := time.Parse(layout, "01/31/2000 12:59 AM"); err == nil {
        fmt.Println("Time decoded:", t)
    } else {
        fmt.Println("Failed to decode time:", err)
    }
}
英文:

I am trying to parse a date time string in go. I pass the exact string as the format and get and error parsing time "01/31/2000 12:59 AM": hour out of range.
I am getting that string from an input. How can I make this work?

Here is the code (https://play.golang.org/p/Kg9KfFpU2z)

func main() {
	layout := "01/31/2000 12:59 AM"
	if t, err := time.Parse(layout, "01/31/2000 12:59 AM"); err == nil {
		fmt.Println("Time decoded:", t)
	} else {
		fmt.Println("Failed to decode time:", err)
	}
}

答案1

得分: 3

根据你分享的代码,你应该将布局更改为01/02/2006 03:04 AM来修复它:

注意:
如果你使用的是24小时制,你应该将布局中的小时部分改为15而不是03,并且去掉AM部分,例如01/02/2006 15:04

package main

import (
	"fmt"
	"time"
)

func main() {
	layout := "01/02/2006 03:04 AM"
	if t, err := time.Parse(layout, "01/31/2000 12:59 AM"); err == nil {
		fmt.Println("Time decoded:", t)
	} else {
		fmt.Println("Failed to decode time:", err)
	}
}

这里有一篇很好的文章,可以帮助你了解不同的布局。

英文:

Based on your shared code, you should change the layout to 01/02/2006 03:04 AM to fix it:

Note:
If you have 24 hours format, you should change the hour part in layout to 15 instead of 03 and also to get rid of AM part e.g. 01/02/2006 15:04

package main

import (
	"fmt"
	"time"
)

func main() {
	layout := "01/02/2006 03:04 AM"
	if t, err := time.Parse(layout, "01/31/2000 12:59 AM"); err == nil {
		fmt.Println("Time decoded:", t)
	} else {
		fmt.Println("Failed to decode time:", err)
	}
}

Here is a good article that would help you to understand different layouts.

答案2

得分: 0

你的格式需要使用非常特定的日期和时间格式,请参考文档:

https://golang.org/pkg/time/#example_Parse

Parse函数解析一个格式化的字符串并返回它表示的时间值。布局(layout)定义了格式,它展示了参考时间(reference time)的格式,参考时间被定义为:

Mon Jan 2 15:04:05 -0700 MST 2006

所以你需要使用 https://play.golang.org/p/c_Xc_R2OHb 这个链接。

英文:

Your format needs to use a very specific date and time, see the docs:

https://golang.org/pkg/time/#example_Parse

> Parse parses a formatted string and returns the time value it
> represents. The layout defines the format by showing how the reference
> time, defined to be
>
> Mon Jan 2 15:04:05 -0700 MST 2006

So you need https://play.golang.org/p/c_Xc_R2OHb

huangapple
  • 本文由 发表于 2017年3月19日 00:04:39
  • 转载请务必保留本文链接:https://go.coder-hub.com/42876621.html
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