英文:
golang json decode with empty request body
问题
在下面的HTTP处理程序中，我试图区分请求体是否为空：
type Request struct {
A bool `json:"lala"`
B bool `json:"kaka"`
C int32 `json:"cc"`
D int32 `json:"dd"`
}
var (
opts Request
hasOpts bool = true
)
err = json.NewDecoder(r.Body).Decode(&opts)
switch {
case err == io.EOF:
hasOpts = false
case err != nil:
return errors.New("Could not get advanced options: " + err.Error())
}
然而，即使r.Body等于'{}'，hasOpts仍然为true。这是预期的吗？如果是这样，我应该如何检测空的请求体？
英文:
In the following http handler, I try to distinguish whether the request body is empty
type Request struct {
A bool `json:"lala"`
B bool `json:"kaka"`
C int32 `json:"cc"`
D int32 `json:"dd"`
}
var (
opts Request
hasOpts bool = true
)
err = json.NewDecoder(r.Body).Decode(&opts)
switch {
case err == io.EOF:
hasOpts = false
case err != nil:
return errors.New("Could not get advanced options: " + err.Error())
}
However, even with r.Body equals '{}', hasOpts is still true. Is this to be expected? In that case, how should I detect empty request body?
答案1
得分: 5
首先，阅读请求体以检查其内容，然后对其进行解析：
body, err := ioutil.ReadAll(r.Body)
if err != nil {
return err
}
if len(body) > 0 {
err = json.Unmarshal(body, &opts)
if err != nil {
return fmt.Errorf("无法获取高级选项：%s", err)
}
}
英文:
Read the body first, to check its content, then unmarshal it:
body, err := ioutil.ReadAll(r.Body)
if err != nil {
return err
}
if len(body) > 0 {
err = json.Unmarshal(body, &opts)
if err != nil {
return fmt.Errorf("Could not get advanced options: %s", err)
}
}
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