将XML解析为带有标签属性的结构体。

huangapple
go评论108阅读模式
英文:

Go Parse XML to struct by tag attribute

问题

我正在尝试按属性和值解析以下XML。

  1. <result name="response" numFound="10775" start="0" maxScore="0.59509283">
  2.     <doc>
  3.         <str name="cui">c0162311</str>
  4.         <str name="display_title">Androgenetic alopecia</str>
  5.         <str name="source">GHR</str>
  6.         <str name="source_url">http://ghr.nlm.nih.gov/condition/androgenetic-alopecia</str>
  7.         <float name="score">0.59509283</float>
  8.     </doc>

我已经得到了以下结果

  1. type Response struct {
  2. 	StrDoc []Str `xml:"result>doc"`
  3. }
  5. type Str struct {
  6. 	Doc   []Doc   `xml:"str"`
  7. 	Score []Score `xml:"float"`
  8. }
  10. type Doc struct {
  11. 	Key   string `xml:"name,attr"`
  12. 	Value string `xml:",chardata"`
  13. }
  15. type Score struct {
  16. 	Score string `xml:",chardata"`
  17. }

它产生了

  1.   "StrDoc": [
  2.     {
  3.       "Doc": [
  4.         {
  5.           "Key": "cui",
  6.           "Value": "c0162311"
  7.         },
  8.         {
  9.           "Key": "display_title",
  10.           "Value": "Androgenetic alopecia"
  11.         },
  12.         {
  13.           "Key": "source",
  14.           "Value": "GHR"
  15.         },
  16.         {
  17.           "Key": "source_url",
  18.           "Value": "http://ghr.nlm.nih.gov/condition/androgenetic-alopecia"
  19.         }
  20.       ],
  21.       "Score": [
  22.         {
  23.           "Score": "0.59509283"
  24.         }
  25.       ]
  26.     },

期望的输出应该是

  1. "Doc": [
  2.             {
  3.               "cui": "c0162311",
  4.               "display_title": "Androgenetic alopecia",
  5.               "source": "GHR",
  6.               "Value": "GHR",
  7.               "source_url": "http://ghr.nlm.nih.gov/",
  8.               "Score": "0.59509283"
  9.             }
  10.           ]

我已经尝试了几个小时，但还没有找到解决方法。

英文:

I'm trying to parse the following XML by attribute and value.

  1. &lt;result name=&quot;response&quot; numFound=&quot;10775&quot; start=&quot;0&quot; maxScore=&quot;0.59509283&quot;&gt;
  2.     &lt;doc&gt;
  3.         &lt;str name=&quot;cui&quot;&gt;c0162311&lt;/str&gt;
  4.         &lt;str name=&quot;display_title&quot;&gt;Androgenetic alopecia&lt;/str&gt;
  5.         &lt;str name=&quot;source&quot;&gt;GHR&lt;/str&gt;
  6.         &lt;str name=&quot;source_url&quot;&gt;http://ghr.nlm.nih.gov/condition/androgenetic-alopecia&lt;/str&gt;
  7.         &lt;float name=&quot;score&quot;&gt;0.59509283&lt;/float&gt;
  8.     &lt;/doc&gt;

I've come up with the following

  1. type Response struct {
  2. 	StrDoc []Str `xml:&quot;result&gt;doc&quot;`
  3. }
  5. type Str struct {
  6. 	Doc   []Doc   `xml:&quot;str&quot;`
  7. 	Score []Score `xml:&quot;float&quot;`
  8. }
  10. type Doc struct {
  11. 	Key   string `xml:&quot;name,attr&quot;`
  12. 	Value string `xml:&quot;,chardata&quot;`
  13. }
  15. type Score struct {
  16. 	Score string `xml:&quot;,chardata&quot;`
  17. }

which produces

  1.   &quot;StrDoc&quot;: [
  2.     {
  3.       &quot;Doc&quot;: [
  4.         {
  5.           &quot;Key&quot;: &quot;cui&quot;,
  6.           &quot;Value&quot;: &quot;c0162311&quot;
  7.         },
  8.         {
  9.           &quot;Key&quot;: &quot;display_title&quot;,
  10.           &quot;Value&quot;: &quot;Androgenetic alopecia&quot;
  11.         },
  12.         {
  13.           &quot;Key&quot;: &quot;source&quot;,
  14.           &quot;Value&quot;: &quot;GHR&quot;
  15.         },
  16.         {
  17.           &quot;Key&quot;: &quot;source_url&quot;,
  18.           &quot;Value&quot;: &quot;http://ghr.nlm.nih.gov/condition/androgenetic-alopecia&quot;
  19.         }
  20.       ],
  21.       &quot;Score&quot;: [
  22.         {
  23.           &quot;Score&quot;: &quot;0.59509283&quot;
  24.         }
  25.       ]
  26.     },

The desired output would be

  1. &quot;Doc&quot;: [
  2.             {
  3.               &quot;cui&quot;: &quot;c0162311&quot;,
  4.               &quot;display_title&quot;: &quot;Androgenetic alopecia&quot;,
  5.               &quot;source&quot;: &quot;GHR&quot;,
  6.               &quot;Value&quot;: &quot;GHR&quot;,
  7.               &quot;source_url&quot;: &quot;http://ghr.nlm.nih.gov/&quot;,
  8.               &quot;Score&quot;: &quot;0.59509283&quot;
  9.             }
  10.           ]

I've been trying to achieve this for hours and I haven't found a way yet.

答案1

得分: 3

你可以通过使用自定义的UnmarshalXML方法，将内部XML解组为一个map：

  1. type Result struct {
  2.     Doc Doc `xml:"doc"`
  3. }
  5. type Doc struct {
  6.     Elems map[string]string
  7. }
  9. func (doc *Doc) UnmarshalXML(d *xml.Decoder, start xml.StartElement) (err error) {
  10.     type entry struct {
  11.         Key   string `xml:"name,attr"`
  12.         Value string `xml:",chardata"`
  13.     }
  14.     e := entry{}
  15.     doc.Elems = map[string]string{}
  16.     for err = d.Decode(&e); err == nil; err = d.Decode(&e) {
  17.         doc.Elems[e.Key] = e.Value
  18.     }
  19.     if err != nil && err != io.EOF {
  20.         return err
  21.     }
  22.     return nil
  23. }

Playground: https://play.golang.org/p/87v_vTXpB-。

英文:

You can unmarshal inner XML into a map by using a custom UnmarshalXML method:

  1. type Result struct {
  2. 	Doc Doc `xml:&quot;doc&quot;`
  3. }
  5. type Doc struct {
  6. 	Elems map[string]string
  7. }
  9. func (doc *Doc) UnmarshalXML(d *xml.Decoder, start xml.StartElement) (err error) {
  10. 	type entry struct {
  11. 		Key   string `xml:&quot;name,attr&quot;`
  12. 		Value string `xml:&quot;,chardata&quot;`
  13. 	}
  14. 	e := entry{}
  15. 	doc.Elems = map[string]string{}
  16. 	for err = d.Decode(&amp;e); err == nil; err = d.Decode(&amp;e) {
  17. 		doc.Elems[e.Key] = e.Value
  18. 	}
  19. 	if err != nil &amp;&amp; err != io.EOF {
  20. 		return err
  21. 	}
  22. 	return nil
  23. }

Playground: https://play.golang.org/p/87v_vTXpB-.

huangapple
  • 本文由 发表于 2017年3月10日 22:53:27
  • 转载请务必保留本文链接：https://go.coder-hub.com/42721278.html
  • go
  • xml
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