英文:
json.Unmarshal not decoding into inner interface{} correctly
问题
我正在为Golang开发一个Telegram Bot API的包装器（我知道已经有一些了，但我这样做是为了学习）。我有一个Response结构体：
type Response struct {
Ok bool `json:"ok"`
ErrorCode int64 `json:"error_code"`
Description string `json:"description"`
Result interface{} `json:"result"`
}
我无法确定Result的实际类型：Telegram服务器可能返回很多不同的类型；我为每个类型都创建了一个结构体，但我不知道Result会是哪个类型。当我将HTTP响应的JSON解析为Response结构体时，除了Result之外，其他都可以正确加载。
在一个我确定Result将是User类型的函数中，我尝试使用user := resp.Result.(*User)，但我在运行时遇到以下错误：panic: interface conversion: interface {} is map[string]interface {}, not *tgbot.User。所以，Result是一个map[string]interface{}。我该如何将其转换为*User类型？
谢谢任何回答。
英文:
I'm developing a Telegram Bot API wrapper for Golang (I know there are already some but I'm doing this for learning). I have a Response struct:
type Response struct {
Ok bool `json:"ok"`
ErrorCode int64 `json:"error_code"`
Description string `json:"description"`
Result interface{} `json:"result"`
}
I can't know the actual type of Result: a lot can be returned by Telegram servers; I made a struct for each one, but I don't know which one will be in Result.
When Unmarshaling a JSON from an HTTP response into the Response struct, everything is loaded correctly, except Result.
In a function where I am sure Result will be an User (for example), I'm doing user := resp.Result.(*User), but I get the following error at runtime:
panic: interface conversion: interface {} is map[string]interface {}, not *tgbot.User. So, Result is a map[string]interface{}. How can I transform it into a *User?
Thanks for any answers.
答案1
得分: 6
将其转换为json.RawMessage，并在第二步进行解组，当您确定其类型时。
请查看https://golang.org/pkg/encoding/json/#RawMessage上的示例。
英文:
Make it a json.RawMessage and unmarshal it in a second step, when you're sure what type it is.
Take a look at the examples at https://golang.org/pkg/encoding/json/#RawMessage.
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