英文:
How to fmt.Println() memory not allocated by the go program?
问题
我想打印当前程序从0x10000到0x50000的虚拟内存内容（在我的系统上包含一个系统调用跳板的区域）。
package main
import (
"syscall"
"unsafe"
)
func main() {
syscall.Syscall(SYS_WRITE, uintptr(1), uintptr(unsafe.Pointer(0x10000)), uintptr(0x40000))
}
然而，当我尝试编译时，我得到了以下错误：
cannot convert 65536 (type int) to type unsafe.Pointer
在我的情况下，cgo 被禁用了（import "C" 在编译时失败）。
另外，syscall.Syscall(SYS_WRITE 是唯一的方法吗？
英文:
I’d like to print the virtual memory content of the current program from 0x10000 to 0x50000 (an area containing a syscall trampoline on my system).
package main
import (
"syscall"
"unsafe"
)
func main() {
syscall.Syscall(SYS_WRITE, uintptr(1), uintptr(unsafe.Pointer(0x10000)), uintptr(0x40000))
}
However when I tried to compile I’m getting that error :
cannot convert 65536 (type int) to type unsafe.Pointer
In my case,cgo is disabled (import "C" fails at compile time).
Also does syscall.Syscall(SYS_WRITE is the only way to do it ?
答案1
得分: 2
你可以将该地址转换为字节切片，然后将其传递给任何Write方法。
要将地址0x10000转换为长度为0x30000的字节切片，你可以使用以下代码：
mem := (*[1 << 30]byte)(unsafe.Pointer(uintptr(0x10000)))[:0x30000:0x30000]
如果大小始终是静态的，你可以直接将数组设置为正确的大小：
mem := (*[0x30000]byte)(unsafe.Pointer(uintptr(0x10000)))[:]
请注意，这是Go语言的代码示例。
英文:
You can convert that address to a slice of bytes, which can then be passed to any Write method.
To convert the address 0x10000 to a slice of bytes with a length of 0x30000, you would use
mem := (*[1 << 30]byte)(unsafe.Pointer(uintptr(0x10000)))[:0x30000:0x30000]
If the size is always static, you could just set the array to the proper size to start
mem := (*[0x30000]byte)(unsafe.Pointer(uintptr(0x10000)))[:]
答案2
得分: 1
你面临的直接问题是，你应该将0x10000直接转换为uintptr，而不是通过unsafe.Pointer进行转换。我不知道修复这个问题是否会解决你的其他问题。
英文:
The immediate problem you are facing is that you should convert 0x10000 directly to uintptr instead of through unsafe.Pointer. I don't know if fixing that will solve the rest of your problem or not.
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