英文:
Gorilla mux http package
问题
我正在使用Gorilla mux作为我的Golang应用程序中的路由器和调度程序，并且我有一个 - 我认为 - 简单的问题：
在我的main函数中，我创建了一个路由器：r := mux.NewRouter()。几行之后，我注册了一个处理程序：r.HandleFunc("/", doSomething)。
到目前为止都很好，但是现在我的问题是，我有一个包，它将处理程序添加到Golang的http包而不是我的mux路由器。就像这样：
func AddInternalHandlers() {
http.HandleFunc("/internal/selfdiagnose.html", handleSelfdiagnose)
http.HandleFunc("/internal/selfdiagnose.xml", handleSelfdiagnose)
http.HandleFunc("/internal/selfdiagnose.json", handleSelfdiagnose)
}
如你所见，它将处理程序添加到http.HandleFunc而不是mux.HandleFunc。有没有办法在不修改包本身的情况下解决这个问题？
工作示例
package main
import (
"fmt"
"log"
"net/http"
selfdiagnose "github.com/emicklei/go-selfdiagnose"
"github.com/gorilla/mux"
)
func homeHandler(w http.ResponseWriter, r *http.Request) {
log.Println("home")
}
func main() {
r := mux.NewRouter()
r.HandleFunc("/", homeHandler)
selfdiagnose.AddInternalHandlers()
// 当将处理程序（nil）替换为mux（r）时，
// 包selfdiagnose中的处理程序将不会“激活”
err := http.ListenAndServe(fmt.Sprintf("%s:%d", "localhost", 8080), nil)
if err != nil {
log.Println(err)
}
}
英文:
I'm using Gorilla mux as my router and dispatcher in my golang apps and I have a -I think- simple question:
In my main, I create a router: r := mux.NewRouter(). A few lines further, I register a handler: r.HandleFunc("/", doSomething).
So far so good, but now my problem is that I have a package which adds handlers to the http package of Golang and not to my mux router. Like this:
func AddInternalHandlers() {
http.HandleFunc("/internal/selfdiagnose.html", handleSelfdiagnose)
http.HandleFunc("/internal/selfdiagnose.xml", handleSelfdiagnose)
http.HandleFunc("/internal/selfdiagnose.json", handleSelfdiagnose)
}
As you can see, it adds handles to the http.HandleFunc and not to the mux-handleFunc. Any idea how I can fix this without touching the package itself?
Working example
package main
import (
"fmt"
"log"
"net/http"
selfdiagnose "github.com/emicklei/go-selfdiagnose"
"github.com/gorilla/mux"
)
func homeHandler(w http.ResponseWriter, r *http.Request) {
log.Println("home")
}
func main() {
r := mux.NewRouter()
r.HandleFunc("/", homeHandler)
selfdiagnose.AddInternalHandlers()
// when handler (nil) gets replaced with mux (r), then the
// handlers in package selfdiagnose are not "active"
err := http.ListenAndServe(fmt.Sprintf("%s:%d", "localhost", 8080), nil)
if err != nil {
log.Println(err)
}
}
答案1
得分: 1
好的，以下是翻译好的内容：
嗯，在你的情况下，解决方案很简单。
selfdiagnose包的作者选择将handlers本身设为公开，所以你可以直接使用它们：
r.HandleFunc("/", homeHandler)
// 直接使用handlers，但你需要自己命名一个路由
r.HandleFunc("/debug", selfdiagnose.HandleSelfdiagnose)
工作示例：https://gist.github.com/miku/9836026cacc170ad5bf7530a75fec777
英文:
Well, in your particular case, the solution is easy.
The author of the selfdiagnose package choose to make handlers themselves public, so you can just use them directly:
r.HandleFunc("/", homeHandler)
// use the handlers directly, but you need to name a route yourself
r.HandleFunc("/debug", selfdiagnose.HandleSelfdiagnose)
Working example: https://gist.github.com/miku/9836026cacc170ad5bf7530a75fec777
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