英文:
GO Lang decode JSON (simple array not being picked up)
问题
结构体和JSON在Go语言中并不是很有趣。
我有一个简单的JSON示例和一个结构体。一切似乎都被正确解析了，但是由于某种原因数组没有被获取到。
有人能告诉我可能遗漏了什么吗？
代码---
package main
import (
"encoding/base64"
"fmt"
"encoding/json"
)
type Oauth struct {
Aud string `json:"aud"`
Cid string `json:"cid"`
Exp int `json:"exp"`
Iat int `json:"iat"`
Iss string `json:"iss"`
Jti string `json:"jti"`
Scp []string `json:"scp"`
Sub string `json:"sub"`
UID string `json:"uid"`
Ver int `json:"ver"`
}
func main () {
// 这是字符串 { "ver":1,"jti":"AT.zgv9oQpw-7l3BCg6Xb5NCG2Pf8zxgiQa1EUBXycmaDk","iss":"https://companyx.okta.com/oauth2/aus1a4ibdat0JYw5s1d8","aud":"http://localhost","iat":1484538606,"exp":1484542206,"cid":"3jmNvVCFZ5F6lWOzIONO","uid":"00uy74c0h7NGTLBSXQOC","scp":["read","remove","reserve"],"sub":"oktaadmin@okta.com"}
encoded := "eyJ2ZXIiOjEsImp0aSI6IkFULnpndjlvUXB3LTdsM0JDZzZYYjVOQ0cyUGY4enhnaVFhMUVVQlh5Y21hRGsiLCJpc3MiOiJodHRwczovL2NvbXBhbnl4Lm9rdGEuY29tL29hdXRoMi9hdXMxYTRpYmRhdDBKWXc1czFkOCIsImF1ZCI6Imh0dHA6Ly9sb2NhbGhvc3QiLCJpYXQiOjE0ODQ1Mzg2MDYsImV4cCI6MTQ4NDU0MjIwNiwiY2lkIjoiM2ptTnZWQ0ZaNUY2bFdPeklPTk8iLCJ1aWQiOiIwMHV5NzRjMGg3TkdUTEJTWFFPQyIsInNjcCI6WyJyZWFkIiwicmVtb3ZlIiwicmVzZXJ2ZSJdLCJzdWIiOiJva3RhYWRtaW5Ab2t0YS5jb20ifQ"
data, _ := base64.StdEncoding.DecodeString(encoded)
fmt.Println(string(data))
fmt.Println ("")
var x Oauth
json.Unmarshal([]byte(data), &x)
fmt.Printf ("%+v",x.Scp);
}
结果始终是一个空数组 []
英文:
Structs and JSON are not super fun in Go.
I have a simple example of some JSON, and a struct. Everything seems to get parsed Okay, but for some reason the array does not get picked up.
Can anyone tell me what I might be missing.
Code---
package main
import (
"encoding/base64"
"fmt"
"encoding/json"
)
type Oauth struct {
Aud string `json:"aud"`
Cid string `json:"cid"`
Exp int `json:"exp"`
Iat int `json:"iat"`
Iss string `json:"iss"`
Jti string `json:"jti"`
Scp []string `json:"scp"`
Sub string `json:"sub"`
UID string `json:"uid"`
Ver int `json:"ver"`
}
func main () {
// This is the String {"ver":1,"jti":"AT.zgv9oQpw-7l3BCg6Xb5NCG2Pf8zxgiQa1EUBXycmaDk","iss":"https://companyx.okta.com/oauth2/aus1a4ibdat0JYw5s1d8","aud":"http://localhost","iat":1484538606,"exp":1484542206,"cid":"3jmNvVCFZ5F6lWOzIONO","uid":"00uy74c0h7NGTLBSXQOC","scp":["read","remove","reserve"],"sub":"oktaadmin@okta.com"}
encoded := "eyJ2ZXIiOjEsImp0aSI6IkFULnpndjlvUXB3LTdsM0JDZzZYYjVOQ0cyUGY4enhnaVFhMUVVQlh5Y21hRGsiLCJpc3MiOiJodHRwczovL2NvbXBhbnl4Lm9rdGEuY29tL29hdXRoMi9hdXMxYTRpYmRhdDBKWXc1czFkOCIsImF1ZCI6Imh0dHA6Ly9sb2NhbGhvc3QiLCJpYXQiOjE0ODQ1Mzg2MDYsImV4cCI6MTQ4NDU0MjIwNiwiY2lkIjoiM2ptTnZWQ0ZaNUY2bFdPeklPTk8iLCJ1aWQiOiIwMHV5NzRjMGg3TkdUTEJTWFFPQyIsInNjcCI6WyJyZWFkIiwicmVtb3ZlIiwicmVzZXJ2ZSJdLCJzdWIiOiJva3RhYWRtaW5Ab2t0YS5jb20ifQ"
data, _ := base64.StdEncoding.DecodeString(encoded)
fmt.Println(string(data))
fmt.Println ("")
var x Oauth
json.Unmarshal([]byte(data), &x)
fmt.Printf ("%+v",x.Scp);
}
The result is always an Empty Array []
答案1
得分: 2
编码后的字符串不是有效的 JSON，很容易检测到，因为您在 Unmarshal 上忽略了一个重要的错误，请尝试以下代码：
err := json.Unmarshal(data, &x)
fmt.Println(err)
看起来您错过了 JSON 的最后一个 '}'。
英文:
The encoded string isn't a valid JSON, easy to detect because you're ignoring an important error on Unmarshal, try this:
err := json.Unmarshal(data, &x)
fmt.Println(err)
It looks like you missed the last '}' of your JSON.
答案2
得分: 0
你的 base64 编码字符串无效：
输入字节 404 处存在非法的 base64 数据。
英文:
Your base64-encoded string is not valid:
illegal base64 data at input byte 404
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