将时间戳解组为time.Time类型

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英文:

Unmarshaling epoch timestamp into time.Time

问题

使用此结构运行Decode()会导致“timestamp”列出现错误:

type Metrics struct {
        Id        int       `orm:"column(id);auto"`
        Name      string    `orm:"column(name);size(255);null" json:"metric_name"`
        Lon       float64   `orm:"column(lon);null" json:"lon"`
        Timestamp time.Time `orm:"column(timestamp);type(datetime)" json:"timestamp,omitempty"`
}

错误信息:

 将时间“1352289160”解析为“2006-01-02T15:04:05Z07:00”时出错:无法将“1352289160”解析为“”

如何将其解析为time.Time值?

谢谢

英文:

Running Decode() with this struct produces an error with the 'timestamp' column:

type Metrics struct {
        Id        int       `orm:"column(id);auto"`
        Name      string    `orm:"column(name);size(255);null" json:"metric_name"`
json:"lon"`
        Timestamp time.Time `orm:"column(timestamp);type(datetime)" json:"timestamp;omitempty"`

}

The error:

 parsing time "1352289160" as ""2006-01-02T15:04:05Z07:00"": cannot parse "1352289160" as """

How can I parse it into a time.Time value?

Thank you

答案1

得分: 5

如果你愿意将时间戳作为Unix时间(我假设是这样),只需将字段声明为int64,例如:

type Metrics struct {
    ...
    Timestamp int64 `orm:"column(timestamp);type(datetime)" json:"timestamp,omitempty"`
}

然后,你可以使用以下代码将其转换为Go的Time类型:

var m Metrics
...
When := time.Unix(m.Timestamp, 0)

另一种选择是为Metrics类型编写自定义的UnmarshalJSON处理程序:

func (this *Metrics) UnmarshalJSON(data []byte) error {
    var f interface{}
    err := json.Unmarshal(data, &f)
    if err != nil { return err }
    m := f.(map[string]interface{})
    for k, v := range m {
        switch k {
        case "metric_name": this.Name = v.(string)
        case "timestamp": this.Timestamp = time.Unix(int64(v.(float64)), 0)
        ...
        }
    }
}

然后,你在结构体中将获得正确的time.Time值,这样处理起来更方便。

英文:

If you're okay to have the timestamp as unix time (I assume that what it is) just declare the field as int64, ie

type Metrics struct {
    ...
	Timestamp   int64   `orm:"column(timestamp);type(datetime)" json:"timestamp;omitempty"`
}

You can then convert it to Go's Time type with

var m Metrics 
...
When := time.Unix(m.Timestamp, 0)

Another option is to write custom UnmarshalJSON handler for the Metrics type:

func (this *Metrics) UnmarshalJSON(data []byte) error {
	var f interface{}
	err := json.Unmarshal(data, &f)
	if err != nil { return err; }
	m := f.(map[string]interface{})
	for k, v := range m {
		switch k {
		case "metric_name": this.Name  = v.(string)
		case "timestamp": this.Timestamp = time.Unix(int64(v.(float64)), 0)
        ...
        }
    }
}

Then you have proper time.Time value in struct which makes working with it easier.

huangapple
  • 本文由 发表于 2017年1月11日 22:20:07
  • 转载请务必保留本文链接:https://go.coder-hub.com/41593301.html
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