英文:
Can I range over a struct that is just a []struct?
问题
我有一些定义如下的结构体：
type Thing struct {
Name string
}
type ThingList []Thing
我试图按以下方式遍历ThingList：
thingList := GetThingListFilledWithValues()
for _, v := range thingList {
v.DoStuffToThing()
}
它报错说无法遍历thingList，因为它不是一个切片，而是一个type ThingList。
在知道它的根是一个切片的情况下，我该如何遍历type ThingList？
编辑：
所以显然，我在这里的帖子中并不完全正确。我尝试遍历的不是type ThingList，而是type *ThingList，这导致了错误。所以你可以遍历类型为[]Struct的listStruct，但不能遍历*listStruct。
感谢大家帮助我找到答案。
英文:
I have some structs that are defined as follows:
type Thing struct {
Name string
}
type ThingList []Thing
I am trying to range over ThingList as follows:
thingList := GetThingListFilledWithValues()
for _, v := range thingList {
v.DoStuffToThing()
}
It throws an error saying that you can't range over thingList because it's not a slice, but a type ThingList.
How can I range over type ThingList knowing that at it's root, it's a slice?
EDIT:
So apparently, I wasn't fully correct in my post here. Instead of type ThingList being incorrect, it was a type *ThingList that I was trying to range over, which it failed on. So you can range over a listStruct with type []Struct, just not a *listStruct.
Thanks for helping me find the answer, everybody.
答案1
得分: 7
你需要将你的新类型的实例作为函数的返回值。你可能从GetThingListFilledWithValues()函数中返回了错误的内容。
例如：
func GetThingListFilledWithValues() ThingList {
return ThingList{
Thing{Name: "One"},
Thing{Name: "Two"},
}
}
然后可以这样使用：
thingList := GetThingListFilledWithValues()
for _, v := range thingList {
v.DoStuffToThing()
}
这是在Go Playground上的完整示例：https://play.golang.org/p/6lGdbBsQgJ
英文:
You need to use an instance of your new type as the return from your function. You must be returning the wrong thing from GetThingListFilledWithValues()
For example:
func GetThingListFilledWithValues() ThingList {
return ThingList{
Thing{Name: "One"},
Thing{Name: "Two"},
}
}
And use it like so
thingList := GetThingListFilledWithValues()
for _, v := range thingList {
v.DoStuffToThing()
}
Here's the full example in the go playground https://play.golang.org/p/6lGdbBsQgJ
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