Time duration to string 2h instead 2h0m0s

The default time.Duration String method formats the duration with adding 0s for minutes and 0m0s for hours. Is there function that I can use that will produce 5m instead 5m0s and 2h instead 2h0m0s ... or I have to implement my own?

Foreword: I released this utility in github.com/icza/gox, see timex.ShortDuration().

Not in the standard library, but it's really easy to create one:

func shortDur(d time.Duration) string {
	s := d.String()
	if strings.HasSuffix(s, "m0s") {
		s = s[:len(s)-2]
	}
	if strings.HasSuffix(s, "h0m") {
		s = s[:len(s)-2]
	}
	return s
}

Testing it:

h, m, s := 5*time.Hour, 4*time.Minute, 3*time.Second
ds := []time.Duration{
	h + m + s, h + m, h + s, m + s, h, m, s,
}

for _, d := range ds {
	fmt.Printf("%-8v %v\n", d, shortDur(d))
}

Output (try it on the Go Playground):

5h4m3s   5h4m3s
5h4m0s   5h4m
5h0m3s   5h0m3s
4m3s     4m3s
5h0m0s   5h
4m0s     4m
3s       3s

You can just round the duration like this:

		func RountTime(roundTo string, value time.Time) string {
			since := time.Since(value)
			if roundTo == "h" {
				since -= since % time.Hour
			}
			if roundTo == "m" {
				since -= since % time.Minute
			}
			if roundTo == "s" {
				since -= since % time.Second
			}
			return since.String()
		}