英文:
How do I replace a double quote in json string and regular expressions?
问题
如何在 JSON 字符串和正则表达式中替换双引号？
输入的 JSON 如下：
"RegDateTime" : 1481641851263, "Code":"123213",....
输出应该是：
"RegDateTime" : "1481641851263", "Code":"123213",....
我只想修复 JSON 键值对中的 RegDateTime。请在 Go 语言中提供任何正则表达式，并用双引号进行替换。
英文:
How do I replace a double quote in json string and regular expressions?
Input Json is:
"RegDateTime" : 1481641851263, "Code":"123213",....
and Output should be:
"RegDateTime" : "1481641851263", "Code":"123213",....
I want to fix only json key value that is RegDateTime.
Please suggest any regular expression and replace with double quote in go language.
答案1
得分: 1
func ReplaceAllNumber(json string) (string) {re := regexp.MustCompile("(:\\s*)(\\d+)(\\s*[,}\\]])")return re.ReplaceAllString(json, "$1\"$2\"$3")}func ReplaceNumberWithField(json string, fieldName string) (string) {regString := fmt.Sprintf("(\"%s\"\\s*:\\s*)(\\d+)(\\s*[,}\\]])", fieldName)re := regexp.MustCompile(regString)return re.ReplaceAllString(json, "$1\"$2\"$3")}
<details><summary>英文:</summary>func ReplaceAllNumber(json string)(string) {re := regexp.MustCompile("(:\\s*)(\\d+)(\\s*[,}\\]])")return re.ReplaceAllString(json, "$1\"$2\"$3")}func ReplaceNumberWithField(json string, fieldName string)(string) {regString := fmt.Sprintf("(\"%s\"\\s*:\\s*)(\\d+)(\\s*[,}\\]])", fieldName)re := regexp.MustCompile(regString)return re.ReplaceAllString(json, "$1\"$2\"$3")}[Run Online][1][1]: https://play.golang.org/p/IzlfVWW1FQ</details>
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