Create Struct instance with initialization from slices of data golang

I have a data with array of array.

> data := [][]int{{1,2,3}, {4,5,6}}

and struct
> type A struct {
I, J, K int
}

Now I want to create instance run time for struct A with each array from data, How do I achieve that? If reflect is a way, then tell how?

This is just an example that I want to show you. But let's say if struct A contains 26 fields from A to Z with type of int and I have 100 slices of data from which I can create/init my struct A, then how it could be possible without using dot notation on struct and just looping over field index and assign that field from slice data?

package main

import (
	"fmt"
)

type A struct {
	I, J, K int
}

func main() {
	data := [][]int{
		{1, 2, 3},
		{4, 3, 2},
	}

	var a A
	// create instance of type A with params
	// initialization for each array in data
	fmt.Println(a)
}

Please help me at this link: https://play.golang.org/p/rYuoajn5Ln

I'm not sure if that is what you are looking for, but you can create those objects in a simple loop:

func main() {
	data := [][]int{
    	{1, 2, 3},
	    {4, 3, 2},
	}

	for _, intArr := range data {
    	a := NewA(intArr)
        // a:= A{I: ints[0], J: ints[1], K: ints[2]}
	
	    fmt.Println(a)
    }
}

Full solution available at https://play.golang.org/p/j7fxbmu3jp

Here it is, for a more compact version...

Just range over your "data" array of arrays and create a new "A" from each index.

No need to do that in a separate function.

for _, arr := range data {
	a := A{I: arr[0], J: arr[1], K: arr[2]}
	
	fmt.Println(a)
}

Full solution here: https://play.golang.org/p/jyN7f9c-o-