英文:
How can we initialize an array of type struct (which stores the json output) within a struct in golang
问题
我需要初始化以下数据结构，它将存储一个JSON。Attack_plans将保存多个计划，如果我遍历GeneratePlan结构，我需要获取存储的所有计划。
type GeneratePlan struct {Mode string `json:"mode"`Name string `json:"name"`Schema string `json:"schema"`Version string `json:"version"`Attack_plans []struct {Attack_plan *Attack_plan `json:"attack-plan"`} `json:"attack-plans"`}type Attack_plan struct {Attack_resources []struct {Attack_resource *Attack_resource `json:"attack-resource"`} `json:"attack-resources"`}
有人可以提供建议吗？如果在初始化之前需要简化数据结构，请也提出建议。我对golang非常陌生，请忽略最佳实践。感谢任何帮助！
英文:
I need to initialize the following data structure which will store a json. The Attack_plans will hold multiple plans and if I loop through the GeneratePlan struct, I need all the plans that were stored.
type GeneratePlan struct {Mode string `json:"mode"`Name string `json:"name"`Schema string `json:"schema"`Version string `json:"version"`Attack_plans []struct {Attack_plan *Attack_plan `json:"attack-plan"`} `json:"attack-plans"`}type Attack_plan struct {Attack_resources []struct {Attack_resource *Attack_resource `json:"attack-resource"`} `json:"attack-resources"`}
Can anyone please suggest something? If the data structure needs to be simplified before initializing it, then please suggest that as well. I am very new to golang so please ignore the best practices to follow. Any help is appreciated. Thanks!
答案1
得分: 0
为什么不直接使用json.marshal将对象转换为JSON字符串，你就可以得到答案了。
英文:
why don't u just json.marshal your object to a json string, you can got answer
答案2
得分: 0
生成计划 := GeneratePlan{
Mode: "模式",
Name: "名称",
Schema: "模式",
Version: "版本",
Attack_plans: []struct {
Attack_plan *Attack_plan json:"攻击计划"
}{
{Attack_plan: &Attack_plan{[]struct {
Attack_resource *Attack_resource json:"攻击资源"
}{
{Attack_resource: new(Attack_resource)},
{Attack_resource: new(Attack_resource)},
}}},
{Attack_plan: &Attack_plan{[]struct {
Attack_resource *Attack_resource json:"攻击资源"
}{
{Attack_resource: new(Attack_resource)},
{Attack_resource: new(Attack_resource)},
}}},
},
}
英文:
generatePlan := GeneratePlan{Mode: "mode",Name: "name",Schema: "sachema",Version: "version",Attack_plans: []struct {Attack_plan *Attack_plan `json:"attack-plan"`}{{Attack_plan: &Attack_plan{[]struct {Attack_resource *Attack_resource `json:"attack-resource"`}{{Attack_resource: new(Attack_resource)},{Attack_resource: new(Attack_resource)},}}},{Attack_plan: &Attack_plan{[]struct {Attack_resource *Attack_resource `json:"attack-resource"`}{{Attack_resource: new(Attack_resource)},{Attack_resource: new(Attack_resource)},}}},},}
答案3
得分: 0
我找到了解决方案！这简化了上述的数据结构！
type GeneratePlan struct{Mode string `json:"mode"`Name string `json:"name"`Schema string `json:"schema"`Version string `json:"version"`Attack_plans []struct1 `json:"attack-plans"`}type struct1 struct {Attack_plan Attack_plan `json:"attack-plan"`}type Attack_plan struct{Attack_resouces []struct2 `json:"attack-resources"`}type struct2 struct {Attack_resource Attack_resource `json:"attack-resource"`}
以上是翻译好的代码部分。
英文:
I found the solution! This simplifies the above data structure!
type GeneratePlan struct{Mode string `json:"mode"`Name string `json:"name"`Schema string `json:"schema"`Version string `json:"version"`Attack_plans []struct1 `json:"attack-plans"`}type struct1 struct {Attack_plan Attack_plan `json:"attack-plan"`}type Attack_plan struct{Attack_resouces []struct2 `json:"attack-resources"`}type struct2 struct {Attack_resource Attack_resource `json:"attack-resource"`}
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