在Golang中处理并发的HTTP请求

huangapple go评论76阅读模式
英文:

Process concurrent HTTP requests in Golang

问题

我正在尝试处理一个包含200个URL的文件,并使用每个URL进行HTTP请求。每次最多同时处理10个URL(代码应该在10个URL完成处理之前阻塞)。我尝试用Go解决这个问题,但是我一直得到整个文件都被处理,并创建了200个并发连接。

你应该怎么做呢?

英文:

I'm trying to process a file which contains 200 URLs and use each URL to make an HTTP request. I need to process 10 URLs concurrently maximum each time (code should block until 10 URLs finish processing). Tried to solve it in go but I keep getting the whole file processed with 200 concurrent connection created.

for scanner.Scan() { // loop through each url in the file
		// send each url to golang HTTPrequest
		go HTTPrequest(scanner.Text(), channel, &wg)
}
fmt.Println(<-channel)
wg.Wait()

What should i do?

答案1

得分: 9

一个包含10个goroutine的池子,从一个通道中读取数据,应该能满足你的需求。

work := make(chan string)

// 获取原始的200个URL
var urlsToProcess []string = seedUrls()

// 启动一个包含10个goroutine的池子,并从work通道中读取URL
for i := 0; i <= 10; i++ {
  go func(w chan string) {
     url := <-w
  }(work)
}

// 将URL写入work通道,阻塞直到一个worker goroutine能够开始工作
for _, url := range urlsToProcess {
  work <- url
}

清理和请求结果留给你自己来完成。Go通道会阻塞,直到其中一个worker例程能够读取数据。

英文:

A pool of 10 go routines reading from a channel should fulfill your requirements.

work := make(chan string)

// get original 200 urls
var urlsToProcess []string = seedUrls() 

// startup pool of 10 go routines and read urls from work channel 
for i := 0; i&lt;=10; i++ {
  go func(w chan string) {
     url := &lt;-w
  }(work)
}

// write urls to the work channel, blocking until a worker goroutine
// is able to start work
for _, url := range urlsToProcess {
  work &lt;- url
}

Cleanup and request results are left as an exercise for you. Go channels is will block until one of the worker routines is able to read.

答案2

得分: 2

像这样的代码

longTimeAct := func(index int, w chan struct{}, wg *sync.WaitGroup) {
        defer wg.Done()
        time.Sleep(1 * time.Second)
        println(index)
        <-w
}
wg := new(sync.WaitGroup)
ws := make(chan struct{}, 10)
for i := 0; i < 100; i++ {
        ws <- struct{}{}
        wg.Add(1)
        go longTimeAct(i, ws, wg)
}
wg.Wait()
英文:

code like this

longTimeAct := func(index int, w chan struct{}, wg *sync.WaitGroup) {
        defer wg.Done()
        time.Sleep(1 * time.Second)
        println(index)
        &lt;-w
}
wg := new(sync.WaitGroup)
ws := make(chan struct{}, 10)
for i := 0; i &lt; 100; i++ {
        ws &lt;- struct{}{}
        wg.Add(1)
        go longTimeAct(i, ws, wg)
}
wg.Wait()

huangapple
  • 本文由 发表于 2016年11月21日 08:26:56
  • 转载请务必保留本文链接:https://go.coder-hub.com/40711091.html
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