问题

我已经创建了一个名为Url的类型，它应该包含响应体。

type Url struct {
    Address string
    Refresh string
    Watch   string
    Found   bool
    Body    bytes.Buffer // bytes.Buffer不需要初始化
}

使用正确的Address创建了一个Url对象，然后我执行了以下操作：

resp, err := http.Get(url.Address)

现在我想做类似下面的操作，但我无法摆脱它：

io.Copy(url.Body, b) // 将其复制到Url缓冲区

目前，如果需要，可以将Url.Body字段修改为另一种类型。

之后，我想从该缓冲区/写入器/任何其他地方获取字符串，但我认为一旦我解决了前面的复制问题，这将很容易。

祝好，
Le Barde。

英文:

I have made an Url type that should contain the response body.

type Url struct {
	Address string
	Refresh string
	Watch   string
	Found   bool
	Body    bytes.Buffer // bytes.Buffer needs no initialization
}

An Url object is created with the right Address, and then I do

resp, err := http.Get(url.Address)

Now I would like to do something like the following, but I cannot get out of it:

io.Copy(url.Body, b) // Copy that to the Url buffer

As for now, the Url.Body field can be modified to another type if needed.

Afterwards, I want to get the string from that Buffer/Writer/whatever, but I assume this will be easy as soon as I will manage the former copy.

Regards,
Le Barde.

答案1

得分: 1

我猜你想使用ioutil.ReadAll函数，它返回[]byte类型：

resp, err := http.Get(url.Address)
if err != nil {
   // 处理错误
}
defer resp.Body.Close()
url.Body, err = ioutil.ReadAll(resp.Body)

英文:

I guess you want to use ioutil.ReadAll which returns []byte:

resp, err := http.Get(url.Address)
if err != nil {
   // handle error
}
defer resp.Body.Close()
url.Body, err = ioutil.ReadAll(resp.Body)

通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。