英文:
Is it possible to convert JSON variable names on-the-fly in go?
问题
我目前正在实现一个将复杂结构打印成JSON的函数。它需要将变量名转换为小写，这意味着需要在各个地方添加大量的JSON标签。我尝试将结构转换为map，然后更改大小写并转换回来，但这会将int64转换为float64，并且还会弄乱其他一些东西。
有没有一种简便的方法在Go中实现即时转换JSON变量名的方式？
英文:
I'm currently implementing some function that prints a complex structure into JSON. It needs the variable names to be lower-case, which would mean putting a lot of JSON tags all over the place. I tried converting the structure to map, then changing the capitalisation and converting it back, but that converted int64s into float64s and messed a few other things up.
Is there some way to easily convert JSON variable names on-the-fly in go?
答案1
得分: 1
如果地图不适用于您，JSON标签可能是您的最佳选择。
否则，您需要手动修改json.Marshal的输出，它是一个[]byte类型的数据，将其更改为字符串，然后解析并将所有键转换为小写。
英文:
JSON Tags would the your best option, if maps are not an option for you.
Else you would need to manually modify the output of json.Marshal, which is a []byte change it to a string, parse through it and convert all the keys to lower case.
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