英文:
How to deal with Struct having different json key than json response
问题
我有一个名为VideoInfo的结构体，其中有一个名为embedCode的键。我正在查询的API将嵌入代码返回为embed_code。在解组响应时，我该如何确保embed_code被赋值给embedCode？
此外，是否有一种简单的方法可以将一个大的JSON字符串自动转换为结构体，或者只能使用映射（map）来实现？
英文:
I have a struct VideoInfo that has a key in it called embedCode. The API I am querying returns the embed code as embed_code. During unmarshalling the response how do I ensure embed_code goes into embedCode?
Also is there an easy way to take a large json string and automatically turn it into a struct, or can one only use a map?
答案1
得分: 1
首先，结构体的字段必须以大写字母开头才能是公共的。所以你需要像这样写：
type VideoInfo struct {
EmbedCode string `json:"embed_code"`
}
并且查看文档以获取更多信息。
英文:
At first, struct's field must be start from capital letter to be public. So you need something like that:
type VideoInfo struct {
EmbedCode string `json:"embed_code"`
}
And look at documentation for more info.
答案2
得分: 1
关于重新映射字段名，请在结构声明中使用相应的注释：
type VideoInfo struct {
EmbedCode string `json:"embed_code"`
}
编组器/解组器只会处理公共字段，所以你需要将字段名大写。
关于转换整个结构体，是的，很容易实现。声明一个实例用于解组，并将引用传递给json.Unmarshal方法（来自测试）：
data, _ := json.Marshal(request)
var resp response.VideoInfo
if err := json.Unmarshal(data, &resp); err != nil {
t.Errorf("unexpected error, %v", err)
}
英文:
With respect to remapping the field names use the corresponding annotation in the structure declaration:
type VideoInfo struct {
EmbedCode string `json:"embed_code"`
}
The marshaller/un-marshaller will only process public field, so you need to capitalise the field name.
With respect to converting the whole structure, yes it is easy. Declare an instance to un-marshal into and pass a reference to the json.Unmarshal method (from a test):
data, _ := json.Marshal(request)
var resp response.VideoInfo
if err := json.Unmarshal(data, &resp); err != nil {
t.Errorf("unexpected error, %v", err)
}
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