英文:
go: var declared but not used error - how to work around it?
问题
在这个函数中,我得到了一个“声明但未使用”的错误,我不明白 - 我需要以某种方式标记它为“我确实使用了它”吗?
func getString(data map[string]interface{}, name string) (string, error) {
s := data[name]
if reflect.TypeOf(s).Kind() != reflect.String {
return s.(string), nil
}
return "", &apiError{1, "它不是一个字符串"}
}
奇怪的是,我没有从这个函数中得到错误:
func getInt(data map[string]interface{}, name string) (int, error) {
t := data[name]
if reflect.TypeOf(t).Kind() == reflect.Int {
return t.(int), nil
}
return 0, &apiError{1, "它不是一个整数"}
}
此外,对于将它们合并为一个函数的正确方法,您有什么想法?
英文:
In this function I get "s declared and not used" which I don't understand - do I need to somehow tag it as 'really I used it' or something?
func getString(data map[string]interface{}, name string) (string, error) {
s := data[name]
if reflect.TypeOf(s).Kind() != reflect.String {
return s.(string), nil
}
return "", &apiError{1, "it's not a string"}
}
Oddly, I don't get the error from this function:
func getInt(data map[string]interface{}, name string) (int, error) {
t := data[name]
if reflect.TypeOf(t).Kind() == reflect.Int {
return t.(int), nil
}
return 0, &apiError{1, "it's not an int"}
}
Also, any thoughts on the right way to factor these into a single function would be welcomed!
答案1
得分: 1
你的错误来自于在其他地方声明和不使用相同的标识符,因为这段代码在golang.org
上编译和运行都很好:
package main
import "reflect"
func main() {
m := make(map[string]interface{})
m["foo"] = "25"
getString(m, "foo")
}
func getString(data map[string]interface{}, name string) (string, error) {
s := data[name]
if reflect.TypeOf(s).Kind() != reflect.String {
return s.(string), nil
}
return "", nil
}
英文:
Your error comes from (declaring and not) using the same identifier elsewhere because this compiles and runs fine on golang.org
:
package main
import "reflect"
func main() {
m := make(map[string]interface{})
m["foo"] = "25"
getString(m, "foo")
}
func getString(data map[string]interface{}, name string) (string, error) {
s := data[name]
if reflect.TypeOf(s).Kind() != reflect.String {
return s.(string), nil
}
return "", nil
}
答案2
得分: 0
你的代码看起来是正确的,错误无法重现。
当然,你可以将这些代码重构为一个单一的函数,但根据个人喜好可能会有所不同。
type VType int
const (
VInteger VType = iota
VString
VUnknown
)
func getValue(data map[string]interface{}, name string) (VType, int, string) {
switch v := data[name].(type) {
case int:
return VInteger, v, ""
case string:
return VString, 0, v
default:
return VUnknown, 0, ""
}
}
func main() {
m := make(map[string]interface{})
m["foo"] = "25"
switch t, i, s := getValue(m, "foo"); t {
case VInteger:
fmt.Println("int ", i) //do something with int
case VString:
fmt.Println("string ", s) //do something with string
case VUnknown:
err := &apiError{1, "it's not an int"} //do something with err
}
}
希望对你有帮助!
英文:
Your code looks correct, error isn't reproducible.
Sure you can refactor these into a single function, but you may not like it depending of tastes.
type VType int
const (
VInteger VType = iota
VString
VUnknown
)
func getValue(data map[string]interface{}, name string) (VType, int, string) {
switch v := data[name].(type) {
case int:
return VInteger, v, ""
case string:
return VString, 0, v
default:
return VUnknown, 0, ""
}
}
func main() {
m := make(map[string]interface{})
m["foo"] = "25"
switch t, i, s := getValue(m, "foo"); t {
case VInteger:
fmt.Println("int ", i) //do something with int
case VString:
fmt.Println("string ", s) //do something with string
case VUnknown:
err := &apiError{1, "it's not an int"} //do something with err
}
}
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