英文:
SplitN backwards?
问题
我有一个字符串，它的开头总是一个会每次改变的句子，但结尾是时间和日期。例如："我去商店了 12:00 12/12/12" 或者 "我喜欢吐司 11:20 13/10/14"。
我想从这些字符串中提取出时间。是否可以从右侧开始使用 SplitN 函数进行分割？
英文:
I have a string that will always start with a sentence that well change each time but end with time then date. For example "I went to the shop 12:00 12/12/12" or "I like toast 11:20 13/10/14".
I want to extract the time out of these strings. Is it possible to do SplitN starting from the right?
答案1
得分: 1
如果你知道它总是以时间和日期结尾，为什么不用split函数反向操作呢？
package main
import (
"fmt"
"strings"
)
func main() {
s := "我去了商店 12:00 12/12/12"
chunks := strings.Split(s, " ")
time := chunks[len(chunks)-2]
fmt.Println(time)
}
英文:
If you know that it will always end with time and then date why not just go backwards with split?
package main
import (
"fmt"
"strings"
)
func main() {
s := "I went to the shop 12:00 12/12/12"
chunks := strings.Split(s, " ")
time := chunks[len(chunks)-2]
fmt.Println(time)
}
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