英文:
How can I unmarshall JSONp returned from a request?
问题
我正在尝试使用美国农业部农贸市场目录API，通过邮政编码获取附近农贸市场的数据。我将响应的未解组的主体存储在以下结构中：
type marketResponse struct {MapsLink string `json:"GoogleLink"`Address string `json:"Address"`Schedule string `json:"Schedule"`Products string `json:"Products"`}
使用以下代码：
//TODO: location: "http://search.ams.usda.gov/farmersmarkets/v1/data.svc/locSearch?lat=" + lat + "&lng=" + lngresp, err := http.Get("http://search.ams.usda.gov/farmersmarkets/v1/data.svc/zipSearch?zip=" + zipcode)if err != nil {log.Printf("无法搜索邮政编码 %s：%v", zipcode, err)}defer func() {if err := resp.Body.Close(); err != nil {log.Println(err)}}()body, err := ioutil.ReadAll(resp.Body)if err != nil {log.Println(err)}newMarket := &marketResponse{}if err := json.Unmarshal(body, newMarket); err != nil {log.Println(err)}log.Println("响应：" + newMarket.Address)
问题是，响应主体是JSONp格式，而我正在使用JSON解组。我该如何使用外部包或其他方法来解组JSONp格式的数据呢？
英文:
I'm attempting to use the USDA's Farmers Market Directory API to receive a data about where nearby farmer's markets are located, using a zip code. I store the unmarshalled body of the response in:
type marketResponse struct {MapsLink string `json:"GoogleLink"`Address string `json:"Address"`Schedule string `json:"Schedule"`Products string `json:"Products"`}
Using the code:
//TODO: location: "http://search.ams.usda.gov/farmersmarkets/v1/data.svc/locSearch?lat=" + lat + "&lng=" + lngresp, err := http.Get("http://search.ams.usda.gov/farmersmarkets/v1/data.svc/zipSearch?zip=" + zipcode)if err != nil {log.Printf("Could net search zipcode %s: %v", zipcode, err)}defer func() {if err := resp.Body.Close(); err != nil {log.Println(err)}}()body, err := ioutil.ReadAll(resp.Body)if err != nil {log.Println(err)}newMarket := &marketResponse{}if err := json.Unmarshal(body, newMarket); err != nil {log.Println(err)}log.Println("response: " + newMarket.Address)
The problem is, the response body is in JSONp, and I'm unmarshalling in JSON. How can I unmarshal in JSONp, using an external package, or not?
答案1
得分: 2
响应体是JSON格式的，根据响应的Content-Type:application/json; charset=utf-8头部字段。
问题在于你的marketResponse结构体与返回的JSON没有关联。使用JSON-to-Go，你的结构体应该如下所示：
type MarketResponse struct {Results []Result `json:"results"`}type Result struct {ID string `json:"id"`Marketname string `json:"marketname"`}
目前不清楚你现有的marketResponse结构体在这里的作用，因为两个API端点都没有返回该结构体的数据。
另外，你应该处理（或返回）错误，而不仅仅是记录它们；记录错误仍然意味着你的函数会继续处理未处理的错误。当遇到空的响应体或JSON解析错误时，你的代码可能会发生恐慌。
英文:
The response body is JSON - as per the response's Content-Type:application/json; charset=utf-8 header.
The issue is that your marketResponse struct bears no relation to the JSON returned. Using JSON-to-Go, your struct should look like:
type MarketResponse struct {Results []Result `json:"results"`}type Result struct {ID string `json:"id"`Marketname string `json:"marketname"`}
It's not clear where your existing marketResponse struct fits here, as neither API endpoint returns data with that structure.
PS: You should handle (or return) your errors and not just log them; logging them still means that your function continues with unhandled error. Your code might then panic when it encounters a nil response body or JSON unmarshalling error.
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