英文:
Go templates range loop is quoting my value
问题
我有一个字符串切片（.Table.PKey.Columns），我想在模板中循环遍历它，生成一个执行一些追加操作的go文件。但是当我在模板中输出$value时，显然Go会为我加上引号，所以它给我报错：
5:27: 期望选择器或类型断言，找到'STRING' "ID"
也就是说，模板输出应该是类似于o.ID的样子，但实际上却变成了类似于o."ID"的样子（我猜测）。
我是否正确地认为这是使用range循环的结果？因为当我直接在其他地方访问变量时（例如，假设我有一个字符串并执行以下操作：o.{{.Table.MyString}}），它工作正常，但是一旦我尝试将range循环结合起来，它似乎就会加上引号。
{{- range $key, $value := .Table.PKey.Columns }}
args = append(args, o.{{$value}})
{{ end -}}
有什么建议吗？谢谢。
英文:
I've got a slice of strings (.Table.PKey.Columns) that I'm trying to loop over in my template to generate a go file that does some appends, but when I output $value in my template, apparently Go is quoting it for me, so it is giving me the error:
5:27: expected selector or type assertion, found 'STRING' "ID"
i.e., instead of the template output looking something like o.ID -- which is what I'm aiming for, it ends up looking something like o."ID" (I presume).
Am I right in my assumption that this is the result of using a range loop? Because it seems when I access variables directly in other places (for example, say I had a string and I did: o.{{.Table.MyString}}) it works fine, but as soon as I try and incorporate a range loop into the mix it seems to be quoting things.
{{- range $key, $value := .Table.PKey.Columns }}
args = append(args, o.{{$value}})
{{ end -}}
Any suggestions? Thank you.
答案1
得分: 3
{{range}}不会对任何内容进行引用。如果在输出中看到"ID"，那么你的输入值就是包含引号的"ID"！
看看这个例子：
func main() {
m := map[string]interface{}{
"Id": "Id1",
"Quoted": `"Id2"`,
"Ids": []string{"Id1", `"Id2"`, "Abc"},
}
t := template.Must(template.New("").Parse(src))
t.Execute(os.Stdout, m)
}
const src = `{{.Id}} {{index .Ids 0}} {{.Quoted}}
{{range $key, $value := .Ids}}{{$value}}
{{end}}
`
输出结果（在Go Playground上尝试）：
Id1 Id1 "Id2"
Id1
"Id2"
Abc
英文:
The {{range}} does not quote anything. If you see "ID" in your output, then your input value is "ID" with quotation marks included!
See this example:
func main() {
m := map[string]interface{}{
"Id": "Id1",
"Quoted": `"Id2"`,
"Ids": []string{"Id1", `"Id2"`, "Abc"},
}
t := template.Must(template.New("").Parse(src))
t.Execute(os.Stdout, m)
}
const src = `{{.Id}} {{index .Ids 0}} {{.Quoted}}
{{range $key, $value := .Ids}}{{$value}}
{{end}}
`
Output (try it on the Go Playground):
Id1 Id1 "Id2"
Id1
"Id2"
Abc
答案2
得分: 0
如果Go模板渲染的变量位于
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