为什么Go语言允许我调用未实现的方法?

huangapple go评论96阅读模式
英文:

Why does Go allow me to call methods that are not implemented?

问题

Go似乎没有强制要求结构体遵循接口。为什么以下代码能够编译通过?

package main

type LocalInterface interface {
    SomeMethod(string) error
    SomeOtherMethod(string) error
}

type LocalStruct struct {
    LocalInterface
    myOwnField string
}

func main() {
    var localInterface LocalInterface = &LocalStruct{myOwnField:"test"}
    
    localInterface.SomeMethod("calling some method")
}

看起来这段代码不应该编译通过,因为SomeMethod没有被实现。但是使用go build命令并没有报错。

运行代码会导致运行时错误:

> go run main.go
panic: runtime error: invalid memory address or nil pointer dereference
[signal 0xc0000005 code=0x0 addr=0x20 pc=0x4013b0]

goroutine 1 [running]:
panic(0x460760, 0xc08200a090)
        C:/Go/src/runtime/panic.go:464 +0x3f4
main.(*LocalStruct).SomeMethod(0xc0820064e0, 0x47bf30, 0x13, 0x0, 0x0)
        <autogenerated>:3 +0x70
main.main()
        C:/Users/kdeenanauth/Documents/git/go/src/gitlab.com/kdeenanauth/structTest/main.go:16 +0x98
exit status 2
英文:

Go doesn't seem to enforce the struct adhering to the interface. Why does the following code compile?
<!-- language: go -->

package main

type LocalInterface interface {
    SomeMethod(string) error
    SomeOtherMethod(string) error
}

type LocalStruct struct {
    LocalInterface
    myOwnField string
}

func main() {
    var localInterface LocalInterface = &amp;LocalStruct{myOwnField:&quot;test&quot;}
    
    localInterface.SomeMethod(&quot;calling some method&quot;)
}

It seems like this should not compile since SomeMethod is not implemented.go build results in no issues.

Running it results in the runtime error:

&gt; go run main.go
panic: runtime error: invalid memory address or nil pointer dereference
[signal 0xc0000005 code=0x0 addr=0x20 pc=0x4013b0]

goroutine 1 [running]:
panic(0x460760, 0xc08200a090)
        C:/Go/src/runtime/panic.go:464 +0x3f4
main.(*LocalStruct).SomeMethod(0xc0820064e0, 0x47bf30, 0x13, 0x0, 0x0)
        &lt;autogenerated&gt;:3 +0x70
main.main()
        C:/Users/kdeenanauth/Documents/git/go/src/gitlab.com/kdeenanauth/structTest/main.go:16 +0x98
exit status 2

答案1

得分: 7

当一个类型被嵌入(例如,在你的例子中,LocalInterface 被嵌入在 LocalStruct 中),Go 会创建一个嵌入类型的字段,并将其方法提升到包含它的类型中。

所以以下声明:

type LocalStruct struct {
    LocalInterface
    myOwnField string
}

等同于

type LocalStruct struct {
    LocalInterface LocalInterface
    myOwnField string
}

func (ls *LocalStruct) SomeMethod(s string) error {
    return ls.LocalInterface.SomeMethod(s)
}

你的程序因为 LocalInterface 字段是 nil 而导致空指针解引用的恐慌。

以下程序“修复”了这个恐慌(http://play.golang.org/p/Oc3Mfn6LaL):

package main

type LocalInterface interface {
    SomeMethod(string) error
}

type LocalStruct struct {
    LocalInterface
    myOwnField string
}

type A int

func (a A) SomeMethod(s string) error {
    println(s)
    return nil
}

func main() {
    var localInterface LocalInterface = &LocalStruct{
        LocalInterface: A(10),
        myOwnField:     "test",
    }

    localInterface.SomeMethod("calling some method")
}
英文:

When a type is embedded (in your example LocalInterface is embedded inside LocalStruct), Go creates a field of the embedded type and promotes its methods to the enclosing type.

So the following declaration

type LocalStruct struct {
    LocalInterface
    myOwnField string
}

is equivalent to

type LocalStruct struct {
    LocalInterface LocalInterface
    myOwnField string
}

func (ls *LocalStruct) SomeMethod(s string) error {
    return ls.LocalInterface.SomeMethod(s)
}

Your program panics with nil pointer dereference because LocalInterface field is nil.

The following program "fixes" the panic (http://play.golang.org/p/Oc3Mfn6LaL):

package main

type LocalInterface interface {
	SomeMethod(string) error
}

type LocalStruct struct {
	 LocalInterface
	myOwnField string
}

type A int

func (a A) SomeMethod(s string) error {
	println(s)
	return nil
}

func main() {
	var localInterface LocalInterface = &amp;LocalStruct{
		LocalInterface: A(10),
		myOwnField:     &quot;test&quot;,
	}

	localInterface.SomeMethod(&quot;calling some method&quot;)
}

答案2

得分: 1

进一步调查后,我发现避免嵌入可以得到适当的错误处理。在我的情况下,这将是首选方法:

package main

type LocalInterface interface {
    SomeMethod(string) error
    SomeOtherMethod(string) error
}

type LocalStruct struct {
    myOwnField string
}

func main() {
    var localInterface LocalInterface = &LocalStruct{myOwnField:"test"}

    localInterface.SomeMethod("calling some method")
}

结果为:

.\main.go:13: 无法将 LocalStruct 字面量(类型 *LocalStruct)分配给 LocalInterface 类型:
        *LocalStruct 未实现 LocalInterface(缺少 SomeMethod 方法)
英文:

Upon further investigation I found that avoiding embedding gets the proper error handling treatment. That would be preferred in my case:
<!-- language: go -->

package main

type LocalInterface interface {
    SomeMethod(string) error
    SomeOtherMethod(string) error
}

type LocalStruct struct {
    myOwnField string
}

func main() {
    var localInterface LocalInterface = &amp;LocalStruct{myOwnField:&quot;test&quot;}

    localInterface.SomeMethod(&quot;calling some method&quot;)
}

Results in:
>.\main.go:13: cannot use LocalStruct literal (type *LocalStruct) as type LocalInterface in assignment:
*LocalStruct does not implement LocalInterface (missing SomeMethod method)

huangapple
  • 本文由 发表于 2016年4月21日 11:10:24
  • 转载请务必保留本文链接:https://go.coder-hub.com/36758900.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定