Get last page http request golang

I am doing an http requestlike this one:

resp, err := http.Get("http://example.com/")

Then I am getting the header link:

link := resp.Header.Get("link")

Which gives me a result like this:

<page=3>; rel="next",<page=1>; rel="prev";<page=5>; rel="last"

Question

How can I parse this into a more legible way? I specifically trying to get the last page but firstand nextpage should useful as well.

I tried with Splitsand Regular expressionswithout success.

Here's a solution of how to match your page numbers.

http://play.golang.org/p/kzurb38Fwx

text := `<page=3>; rel="next",<page=1>; rel="prev";<page=2>; rel="last"`
re := regexp.MustCompile(`<page=([0-9]+)>; rel="next",<page=([0-9]+)>; rel="prev";<page=([0-9]+)>; rel="last"`)
matches:= re.FindStringSubmatch(text)
if matches != nil {
	next := matches[1]
	prev := matches[2]
	last := matches[3]
	fmt.Printf("next = %s, prev = %s, last = %s\n", next, prev, last)
}

Later Edit: you can probably also use the xml package to achieve the same result, by parsing that output as an XML, but you would need to transform your output a bit.

Are you sure that is the format of the output? It looks like one of ; should be a ,.
A single Link http header with multiple values, should be of the format (notice the comma after "prev")

<page=3>; rel="next",<page=1>; rel="prev",<page=5>; rel="last"

The order should be split on , for each link. Split each link on ; for values or key-value pairs, and then if they value matches <(.*=.*)>, discard the angle brackets and use the remaining key and value.