英文:
GO html/template: test equality of two dot variables
问题
我正在发送一个html/template给这个模型：
type MapModel struct {
Networks []*NetworkMeta
WaveKey string
}
Networks字段由另一个类型NetworkMeta定义：
type NetworkMeta struct {
NetworkMetaKey string
}
我使用Networks数组来生成一个html select对象：
<select name="waveKey" id="waveKey">
{{range .Networks}}
<option value="{{ .NetworkMetaKey}}" {{if eq .NetworkMetaKey .WaveKey }} selected="selected" {{end}}>
{{ .NetworkMetaKey }}
</option>
{{end}}
</select>
这里的所有内容都可以正常工作，除了"if eq"的等式测试。该测试返回错误："WaveKey不是*models.NetworkMeta结构类型的字段"。
据我了解，html/template的eq运算符是将一个值与另一个值（或一组值）进行比较，两个值之间用空格分隔。然而，在这种情况下，错误似乎表明对于字段，编译器忽略了空格。
有没有办法使这个等式工作？我需要编写一个自定义函数吗？
谢谢您的帮助。
英文:
I'm sending an html/template this model:
type MapModel struct {
Networks []*NetworkMeta
WaveKey string
}
The Networks field is defined by another type, NetworkMeta:
type NetworkMeta struct {
NetworkMetaKey string
}
I use the Networks array to produce an html select object:
<select name="waveKey" id="waveKey">
{{range .Networks}}
<option value="{{ .NetworkMetaKey}}" {{if eq .NetworkMetaKey .WaveKey }} selected="selected" {{end}}>
{{ .NetworkMetaKey }}
</option>
{{end}}
Everything here works except the "if eq" equality test. That test returns the error: "WaveKey is not a field of struct type *models.NetworkMeta."
As I understand the html/template eq operator, the comparison tests one value against another (or a group of values), the one separated from the rest by a space. In this case, however, the error seems to indicate that for a field, the compiler ignores the space.
Is there any way to make this equality work? Do I need to write a custom func?
Thanks for any help.
答案1
得分: 1
dot正在遍历网络切片，所以它的类型是*NetworkMeta。NetworkMeta没有任何WaveKey字段。
如果你想要访问不同作用域的值，可能需要使用自定义函数。
英文:
dot is iterating through the slice of Networks, so it is of type *NetworkMeta. NetworkMeta doesn't have any fields of WaveKey.
A custom func might be what you want since you are trying to access the values from different scopes.
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