英文:
Golang changing values of a struct inside a method of another struct
问题
我有一个关于结构体的问题,也可能与指针有关,如果我猜得没错的话。
这个结构体有一些字段,还有一个保存切片的字段:
type Bot struct {
    // ...
    connlist []Connection
}
Connection 的定义如下:
type Connection struct {
    conn       net.Conn
    messages   int32
    channels   []string
    joins      int32
    connactive bool
}
我的问题是将 connactive 的值改为 true。
Bot 有一个监听连接的方法:
func (bot *Bot) ListenToConnection(connection Connection) {
    reader := bufio.NewReader(connection.conn)
    tp := textproto.NewReader(reader)
    for {
        line, err := tp.ReadLine()
        if err != nil {
            log.Printf("Error reading from chat connection: %s", err)
            break // 在出现错误时跳出循环
        }
        if strings.Contains(line, "tmi.twitch.tv 001") {
            connection.activateConn()
        }
        if strings.Contains(line, "PING ") {
            fmt.Fprintf(connection.conn, "PONG tmi.twitch.tv\r\n")
        }
        fmt.Fprintf(bot.inconn, line+"\r\n")
    }
}
而 connection.activateConn() 是出现问题的部分,该方法的定义如下:
func (connection *Connection) activateConn() {
    connection.connactive = true
}
这部分实际上是被执行的,所以不是连接没有得到响应之类的问题。
但是,如果我稍后在 Bot 的一个方法中尝试循环遍历它,connactive 总是为 false(默认值)。
for i := 0; i < len(bot.connlist); i++ {
    log.Println(bot.connlist[i].connactive)
}
我认为我是在使用原始连接的副本,而不是已经更改为 connactive = true 的连接。
有什么想法吗?谢谢帮助。
英文:
I have an issue with structs and maybe an issue with pointers, if my guess is correct.
This struct has some fields and a field that holds a slice:
type Bot struct {
    // ...
    connlist []Connection
}
This Connection looks like this:
type Connection struct {
    conn       net.Conn
    messages   int32
    channels   []string
    joins      int32
    connactive bool
}
My problem is changing the value of connactive to true.
Bot has a method that listens to the connection:
func (bot *Bot) ListenToConnection(connection Connection) {
	reader := bufio.NewReader(connection.conn)
	tp := textproto.NewReader(reader)
	for {
		line, err := tp.ReadLine()
		if err != nil {
			log.Printf("Error reading from chat connection: %s", err)
			break // break loop on errors
		}
		if strings.Contains(line, "tmi.twitch.tv 001") {
			connection.activateConn()
		}
		if strings.Contains(line, "PING ") {
			fmt.Fprintf(connection.conn, "PONG tmi.twitch.tv\r\n")
		}
		fmt.Fprintf(bot.inconn, line+"\r\n")
	}
}
And connection.activeConn() is the part that is not working correctly the method looks like this:
func (connection *Connection) activateConn() {
    connection.connactive = true
}
This actually gets executed so it's not an issue of the connection not getting a response or something.
But if I try to loop through it later in a method of Bot, connactive is always false for some reason (which is the default).
for i := 0; i < len(bot.connlist); i++ {
		log.Println(bot.connlist[i].connactive)
}
I think I am working with a copy or so of the original connection and not the changed connection that has connactive = true.
Any ideas? Thanks for the help.
答案1
得分: 10
你的ListenToConnection()方法有一个参数:connection Connection。
当你调用这个ListenToConnection()方法(你没有发布这段代码)时,你传递了一个Connection的值。在Go语言中,所有的东西都是按值传递的,所以会对传递的值进行复制。在ListenToConnection()内部,你操作的是这个副本。你调用了它的activateConn()方法,但是这个方法(它有一个指针接收器)将接收到这个副本的地址(一个局部变量)。
解决方法很简单,将ListenToConnection()的参数改为指针:
func (bot *Bot) ListenToConnection(connection *Connection) {
    // ...
}
使用Bot.connlist中的一个值调用它:
bot.ListenToConnection(&bot.connlist[0])
使用conlist中的每个元素进行调用的for循环:
for i := range bot.connlist {
    bot.ListenToConnection(&bot.conlist[i])
}
**注意!**我故意使用了一个只使用索引而不使用值的for ... range。如果使用带有索引和值的for ... range,或者只使用值,你会观察到相同的问题(connactive仍然为false):
for _, v := range bot.connlist {
    bot.ListenToConnection(&v) // 错误!v也是一个副本
}
因为v也只是一个副本,将它的地址传递给bot.ListenToConnection(),那只会指向副本,而不是connlist切片中的元素。
英文:
Your ListenToConnection() method has one parameter: connection Connection.
When you call this ListenToConnection() method (you didn't post this code), you pass a value of Connection. Everything in Go is passed by value, so a copy will be made of the passed value. Inside ListenToConnection() you operate with this copy. You call its activateConn() method, but that method (which has a pointer receiver) will receive the address of this copy (a local variable).
Solution is simple, change parameter of ListenToConnection() to be a pointer:
func (bot *Bot) ListenToConnection(connection *Connection) {
    // ...
}
Calling it with a value from Bot.connlist:
bot.ListenToConnection(&bot.connlist[0])
A for loop calling it with every elements of conlist:
for i := range bot.connlist {
    bot.ListenToConnection(&bot.conlist[i])
}
Attention! I intentionally used a for ... range which only uses the index and not the value. Using a for ... range with index and value, or just the value, you would observe the same issue (connactive would remain false):
for _, v := range bot.connlist {
    bot.ListenToConnection(&v) // BAD! v is also a copy
}
Because v is also just a copy, passing its address to bot.ListenToConnection(), that would only point to the copy and not the element in the connlist slice.
答案2
得分: 1
需要将以下内容翻译为中文:
需要将连接的切片更改为指向连接的指针。
如果同时更改此属性,则需要使用信号量。
type Bot struct {
	// ...
	conns []*Connection
}
func (bot *Bot) ListenToConnection(c *Connection) {
   // 代码
}
type Connection struct {
	conn         net.Conn
	messages     int32
	channels     []string
	joins        int32
	isActive     bool
	isActiveLock sync.RWMutex
}
func (c *Connection) activateConn() {
	c.isActiveLock.Lock()
	defer c.isActiveLock.Unlock()
    
	c.isActive = true
}
英文:
It needs to be slice of pointers to connections.
And if this property will be changed concurrently, semaphore is necessary.
type Bot struct {
	// ...
	conns []*Connection
}
func (bot *Bot) ListenToConnection(c *Connection) {
   // code
}
type Connection struct {
	conn         net.Conn
	messages     int32
	channels     []string
	joins        int32
	isActive     bool
	isActiveLock sync.RWMutex
}
func (c *Connection) activateConn() {
	c.isActiveLock.Lock()
	defer c.isActiveLock.Unlock()
    
	c.isActive = true
}
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