英文:
Go: http file upload
问题
我正在尝试使用Go编写的客户端上传文件作为附件。我正在使用http multipart CreateFormFile。但是当我这样做时，它将数据作为请求体发送到服务器，而服务器会拒绝该请求。
以下是示例代码：
file, err := os.Open(*img.Filepath)
if err != nil {
return err
}
defer file.Close()
body := &bytes.Buffer{}
writer := multipart.NewWriter(body)
part, err := writer.CreateFormFile("asset", filepath.Base(*img.Filepath))
if err != nil {
return err
}
_, err = io.Copy(part, file)
if err != nil {
return err
}
contentType := writer.FormDataContentType()
err = writer.Close()
if err != nil {
return err
}
request, err := http.NewRequest("POST", API_URL, body)
if err != nil {
return err
}
request.Header.Set("Content-Type", contentType)
values := request.URL.Query()
values.Add("filename", util.GetFileNameWithoutExtension(*img.FileName))
request.URL.RawQuery = values.Encode()
client := &http.Client{}
resp, err := client.Do(request)
if err != nil {
return err
} else {
respBody := &bytes.Buffer{}
_, err = respBody.ReadFrom(resp.Body)
if err != nil {
return err
}
resp.Body.Close()
}
你想知道如何使用Go实现类似于curl中的"key=@val"功能。
英文:
I am trying to upload a file as an attachment from a client written in Go.
I am using http multipart CreateFormFile. When I do this, it sends the data in body to the server which server rejects.
file, err := os.Open(*img.Filepath)
if err != nil {
return err
}
defer file.Close()
body := &bytes.Buffer{}
writer := multipart.NewWriter(body)
part, err := writer.CreateFormFile("asset", filepath.Base(*img.Filepath))
if err != nil {
return err
}
_, err = io.Copy(part, file)
if err != nil {
return err
}
contentType := writer.FormDataContentType()
err = writer.Close()
if err != nil {
return err
}
request, err := http.NewRequest("POST", API_URL, body)
if err != nil {
return err
}
request.Header.Set("Content-Type", contentType)
values := request.URL.Query()
values.Add("filename", util.GetFileNameWithoutExtension(*img.FileName))
request.URL.RawQuery = values.Encode()
client := &http.Client{}
resp, err := client.Do(request)
if err != nil {
return err
} else {
respBody := &bytes.Buffer{}
_, err = respBody.ReadFrom(resp.Body)
if err != nil {
return err
}
resp.Body.Close()
}
When I try the same using curl it works
curl -X POST -F "asset=@filepath" "http://localhost/api/v1/xyz?filename=filename"
How can I implement key=@val functionality with Go?
答案1
得分: 0
最后我检查了CreateFormFile的代码，发现Content-Type被硬编码为application/octet-stream，并带有mime头。我重新实现了相同的方法，并且它起作用。
func CreateFormFile(w *multipart.Writer, fieldname string, filename string) (io.Writer, error) {
h := make(textproto.MIMEHeader)
h.Set("Content-Disposition", fmt.Sprintf(`form-data; name="%s"; filename="%s"`, escapeQuotes(fieldname), escapeQuotes(filename)))
h.Set("Content-Type", "image/jpeg")
return w.CreatePart(h)
}
英文:
Finally I checked the code for CreateFormFile and the Content-Type is hard coded to application/octet-stream with the mime header. I reimplemented the same method on my own and it works.
func CreateFormFile(w *multipart.Writer, fieldname string, filename string) (io.Writer, error) {
h := make(textproto.MIMEHeader)
h.Set("Content-Disposition", fmt.Sprintf(`form-data; name="%s"; filename="%s"`, escapeQuotes(fieldname), escapeQuotes(filename)))
h.Set("Content-Type", "image/jpeg")
return w.CreatePart(h)
}
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