英文:
Building a JSON object with an array as a value
问题
我需要在一个 JSON 对象中发送一个包含以下结构的数组：
{"extent":[-76.0624694824, 36.8856620774, -75.9800720215,36.9449529607]}
我该如何做呢？我不能使用典型的方式：
var jsonprep string = `{"extent":` + []float32{-76.0624694824, 36.8856620774, -75.9800720215, 36.9449529607} + `}`
var jsonStr = []byte(jsonprep)
因为类型不匹配。我正在尝试将其发送到一个期望它是一个数组的服务器，但我得到了以下错误：
请求内容格式错误：
预期的是一个 JsArray，但得到了 "[-76.0624694824, 36.8856620774, -75.9800720215,36.9449529607]"
英文:
I need to send an Array inside a JSON object with the structure:
{"extent":[-76.0624694824, 36.8856620774, -75.9800720215,36.9449529607]}
How would I do this? I can't use the typical:
var jsonprep string = `{"extent":` + []float32{-76.0624694824, 36.8856620774, -75.9800720215, 36.9449529607} + `}`
var jsonStr = []byte(jsonprep)
because of the type mismatch. I am trying to send this to a server that expects it to be an array as I get the error,
The request content was malformed:
Expected List as JsArray, but got "[-76.0624694824, 36.8856620774, -75.9800720215,36.9449529607]"
答案1
得分: 2
如果你期望数组在某个时刻发生变化，可以考虑使用encoding/json包。
然后你可以创建一个JSON对象的结构原型，然后使用json.Marshal()将其序列化为JSON对象的[]byte表示形式，以便进行传输（无论是通过stdio、tcp还是其他方式）。
例如：
type ExampleJSON struct {
Extent []float32 `json:"extent"`
}
func main(){
ex := &ExampleJSON{
Extent: []float32{-76.0624694824, 36.8856620774, -75.9800720215, 36.9449529607},
}
jsonBytes, err := json.Marshal(ex)
if err != nil {
//...
}
}
英文:
If you are expecting that the array will change at some point, consider using the encoding/json package
Then you can create a struct prototype of your JSON object, then use json.Marshal() to serialize it into a []byte representation of the JSON object for transfer (whether by stdio, tcp, whatever).
e.g.
type ExampleJSON struct {
Extent []float32 `json:"extent"`
}
func main(){
var ex := &ExampleJSON{
[]float32{-76.0624694824, 36.8856620774, -75.9800720215, 36.9449529607}
}
jsonBytes, err := json.Marshal(ex)
if err != nil {
//...
}
}
答案2
得分: -1
我过于思考了。答案是：
var jsonprep string = `{"extent":[-76.0624694824, 36.8856620774, -75.9800720215, 36.9449529607]}`
英文:
I was overthinking it. The answer was:
var jsonprep string = `{"extent":[-76.0624694824, 36.8856620774, -75.9800720215, 36.9449529607]}`
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