英文:
Is there a way to ignore an error return value in Golang?
问题
我正在尝试在Go语言中初始化一个结构体，其中一个值是通过strconv.Atoi("val")将字符串转换为int类型并返回错误。
我的问题是：在Golang中有没有一种忽略错误返回值的方法？
ts := &student{
name: td[0],
ssn: td[2],
next: students.next,
age: strconv.Atoi(td[1]),
}
这段代码会报错：
multiple-value strconv.Atoi() in single-value context
如果我加上错误变量err，虽然我不想在结构体中包含它，但会出现使用未在结构体中定义的方法的错误。
英文:
I'm trying to initialize a struct in Go, one of my values is being which returns both an int and an error if one was encountered converted from a string using strconv.Atoi("val").
My question is : Is there a way to ignore an error return value in Golang?
ts := &student{
name: td[0],
ssn: td[2],
next: students.next,
age: strconv.Atoi(td[1]),
}
which gives the error
multiple-value strconv.Atoi() in single-value context
if I add in the err, which i don't want to include in my struct, I will get an error that I am using a method that is not defined in the struct.
答案1
得分: 11
你可以使用左侧的_来忽略返回值，但是在你的示例中使用“复合字面量”初始化样式时，我认为没有任何方法可以这样做。
例如，我可以这样做：returnValue1, _ := SomeFuncThatReturnsAresultAndAnError()，但是如果你在你的示例中尝试这样做：
ts := &student{
name: td[0],
ssn: td[2],
next: students.next,
age, _: strconv.Atoi(td[1]),
}
它也会生成一个编译器错误。
英文:
You can ignore a return value using _ on the left hand side of assignment however, I don't think there is any way to do it while using the 'composite literal' initialization style you have in your example.
IE I can do returnValue1, _ := SomeFuncThatReturnsAresultAndAnError() but if you tried that in your example like;
ts := &student{
name: td[0],
ssn: td[2],
next: students.next,
age, _: strconv.Atoi(td[1]),
}
It will also generate a compiler error.
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