英文:
multiple-value in single-value context no return func
问题
我在Go中有一个简单的函数，它只是向缓冲区写入内容。我没有在函数上设置返回类型，所以我不确定为什么会出现这个错误。这是我的代码：
func Write(buffer *bytes.Buffer, values ...string) {
for _, val := range values {
_, err := buffer.WriteString(val)
if err != nil {
// 打印错误
}
}
_, err := buffer.WriteString(" ")
if err != nil {
// 打印错误
}
}
我在两个调用buffer.WriteString的地方都遇到了问题。这让我相信它与缓冲区上的WriteString方法的返回类型有关，但我对Go的经验不足，无法确定。
如果有帮助，将不胜感激。
编辑：已更新的代码。
英文:
I have a func in Go that simply writes to a buffer. I have no return type set on the func so I am not sure why I am seeing this error. Here is my code:
func Write(buffer *bytes.Buffer, values ...string) {
for _, val := range values
_, err := *buffer.WriteString(val)
if err != nil {
// print error
}
}
_, err := *buffer.WriteString(" ")
if err != nil {
// print error
}
}
It complains at both lines where I have buffer.WriteString. This leads me to believe it has something to do with the return types of the WriteString method on the buffer but I am not experienced enough in Go to know for sure.
Any help would be appreciated.
Edit: Updated code.
答案1
得分: 1
在Go语言中，调用方法时不需要解引用指针。*操作符在buffer.WriteString之前是应用于返回的值。要解引用buffer，你需要写成(*buffer).WriteString，但实际上这并不需要：
func Write(buffer *bytes.Buffer, values ...string) {
for _, val := range values {
_, err := buffer.WriteString(val)
if err != nil {
// 打印错误
}
}
_, err := buffer.WriteString(" ")
if err != nil {
// 打印错误
}
}
英文:
You don't need to dereference pointers to call methods in Go. The * operator before buffer.WriteString is applied to the returned values. To dereference buffer you would need to write (*buffer).WriteString, but that's not needed at all:
func Write(buffer *bytes.Buffer, values ...string) {
for _, val := range values {
_, err := buffer.WriteString(val)
if err != nil {
// print error
}
}
_, err := buffer.WriteString(" ")
if err != nil {
// print error
}
}
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