英文:
Trying to test for an empty self referential struct value in Go
问题
我是你的中文翻译助手，以下是翻译好的内容：
我刚开始学习Go语言，尝试实现一个非常简单的链表。目前，在递归遍历链表时，我试图在node.next为nil/未设置时跳出for循环，但是if条件从未满足。我只能假设该值不是nil，而是指向一个空的Node结构体类型的指针，但我无法确定如何评估它。这是我的代码，非常感谢任何帮助：
package main
import "fmt"
type Node struct {
data string
next *Node
}
func PrintList(node *Node) {
for {
fmt.Println(node.data)
if node.next == nil {
break
} else {
PrintList(node.next)
}
}
}
func main() {
node3 := &Node{data: "three"}
node2 := &Node{data: "two", next: node3}
node1 := &Node{data: "one", next: node2}
PrintList(node1)
}
请注意，我已经更正了代码中的一个错误。在条件判断中，应该使用node.next == nil而不是node.data == nil来检查下一个节点是否为空。
英文:
I am new to Go and am trying to implement a very simple linked list. Currently while recursively traversing the list I am attempting to break out of the for loop if node.next is nil/unset, but the if conditional is never satisfied. I can only assume that the value is not nil, but some sort of pointer to an empty Node struct type, but I can't figure out how to evaluate this. Here is my code, any help would be much appreciated:
package main
import "fmt"
type Node struct {
data string
next *Node
}
func PrintList(node *Node) {
for {
fmt.Println(node.data)
if node.data == nil {
break
} else {
PrintList(node.next)
}
}
}
func main() {
node3 := &Node{data: "three"}
node2 := &Node{data: "two", next: node3}
node1 := &Node{data: "one", next: node2}
PrintList(node1)
}
答案1
得分: 3
修正你的拼写错误：node.next == nil 而不是 node.data == nil。并修复你的递归错误：删除 for 循环。更好的做法是，为了安全起见，检查 node == nil。例如，
package main
import "fmt"
type Node struct {
data string
next *Node
}
func PrintList(node *Node) {
if node == nil {
return
}
fmt.Println(node.data)
PrintList(node.next)
}
func main() {
node3 := &Node{data: "three"}
node2 := &Node{data: "two", next: node3}
node1 := &Node{data: "one", next: node2}
PrintList(node1)
}
输出：
one
two
three
英文:
Fix your typo: node.next == nil not node.data == nil. And fix your recursion error: delete the for loop. Even better, for safety, check for node == nil. For example,
package main
import "fmt"
type Node struct {
data string
next *Node
}
func PrintList(node *Node) {
if node == nil {
return
}
fmt.Println(node.data)
PrintList(node.next)
}
func main() {
node3 := &Node{data: "three"}
node2 := &Node{data: "two", next: node3}
node1 := &Node{data: "one", next: node2}
PrintList(node1)
}
Output:
one
two
three
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论