如何在Go中将函数存储在切片中

huangapple go评论97阅读模式
英文:

How to store functions in a slice in Go

问题

我正在尝试将以下Python功能移植到Golang中。特别是如何将函数存储在切片中并调用它们。在Golang中我该如何做到这一点?

package main

import "fmt"

type Dispatcher struct {
	listeners []func()
}

func (d *Dispatcher) addListener(listener func()) {
	d.listeners = append(d.listeners, listener)
}

func (d *Dispatcher) notifyUpdate() {
	for _, f := range d.listeners {
		f()
	}
}

func beeper() {
	fmt.Println("beep...beep...beep")
}

func pinger() {
	fmt.Println("ping...ping...ping")
}

func main() {
	dispatch := &Dispatcher{}
	dispatch.addListener(beeper)
	dispatch.addListener(pinger)
	dispatch.notifyUpdate()
}

输出:

beep...beep...beep
ping...ping...ping

以上是将Python代码转换为Golang的示例。在Golang中,我们使用函数类型的切片来存储函数,并通过循环调用它们。

英文:

I'm trying to port the following Python functionality to Golang.
Especially, how to store functions in a slice and then call them.
How can I do this in Golang?

class Dispatcher(object):
    def __init__(self):
	    self._listeners = []

    def addlistener(self, listener):
	    self._listeners.append(listener)

    def notifyupdate(self):
	    for f in self._listeners:
		    f()

def beeper():
    print "beep...beep...beep"

def pinger():
    print "ping...ping...ping"

dispatch = Dispatcher()
dispatch.addlistener(beeper)
dispatch.addlistener(pinger)
dispatch.notifyupdate()

output:
beep...beep...beep

ping...ping...ping

答案1

得分: 22

这是一个相当简单的代码:

package main

import "fmt"

func main() {
    var fns []func()
    fns = append(fns, beeper)
    fns = append(fns, pinger)

    for _, fn := range fns {
        fn()
    }
}

func beeper() {
    fmt.Println("beep-beep")
}

func pinger() {
    fmt.Println("ping-ping")
}

Playground: http://play.golang.org/p/xuDsdeRQX3.

英文:

It's pretty easy actually:

package main

import "fmt"

func main() {
	var fns []func()
	fns = append(fns, beeper)
	fns = append(fns, pinger)

	for _, fn := range fns {
		fn()
	}
}

func beeper() {
	fmt.Println("beep-beep")
}

func pinger() {
	fmt.Println("ping-ping")
}

Playground: http://play.golang.org/p/xuDsdeRQX3.

答案2

得分: 1

以下是翻译好的内容:

或者,如果你想要一个更接近的结构(诚然,在这种情况下并不需要):

package main

import "fmt"

type dispatcher struct {
    listeners []func()
}

func (d *dispatcher) addListener(f func()) {
    d.listeners = append(d.listeners, f)
}

func (d *dispatcher) notify() {
    for _, f := range d.listeners {
        f()
    }
}

func ping() {
    fmt.Println("Ping... ping...")
}

func beep() {
    fmt.Println("Beep... beep...")
}

func main() {
    d := dispatcher{}
    d.addListener(ping)
    d.addListener(beep)
    d.notify()
}

Go playground

英文:

Alternatively, if you want an even closer structure (admittedly, not needed, at all, in this case):

package main

import "fmt"

type dispatcher struct {
    listeners []func()
}

func (d *dispatcher) addListener(f func()) {
    d.listeners = append(d.listeners, f)
}

func (d *dispatcher) notify() {
    for _, f := range d.listeners {
	    f()
    }
}

func ping() {
    fmt.Println("Ping... ping...")
}

func beep() {
    fmt.Println("Beep... beep...")
}

func main() {
    d := dispatcher{}
	d.addListener(ping)
    d.addListener(beep)
    d.notify()
}

Go playground

答案3

得分: 0

package main

import "fmt"

func main() {
    var funcs = []func(){}
    funcs = append(funcs, beeper)
    funcs = append(funcs, pinger)
    
    for _, f := range funcs {
        f()
    }
}

func beeper() {
    fmt.Println("I'm a beeper")
}

func pinger() {
    fmt.Println("I'm a pinger")
}

点击此处查看代码。

英文:
package main

import "fmt"

func main() {
	var funcs = []func(){}
	funcs = append(funcs, beeper)
	funcs = append(funcs, pinger)
	
	for _, f := range funcs {
		f()
	}
}

func beeper() {
	fmt.Println("I'm a beeper")
}

func pinger() {
	fmt.Println("I'm a pinger")
}

http://play.golang.org/p/PaClU6Ri4n

答案4

得分: 0

func main(){
var funcSlice []func()
funcSlice = append(funcSlice, f1)
funcSlice = append(funcSlice, f2)
}

func f1(){
fmt.Println("")
}

func f2(){
fmt.Println("")
}

英文:
func main(){
    var funcSlice []func()
    funcSlice = append(funcSlice, f1)
    funcSlice = append(funcSlice, f2)
}

func f1(){  
    fmt.Println("")
}

func f2(){ 
    fmt.Println("")
}

答案5

得分: 0

如果你使用更复杂的函数,你可以这样做:

func addr(instru, beforeg [4]int) [4]int {
    beforeg[instru[3]] = beforeg[instru[1]] + beforeg[instru[2]]
    return beforeg
}

func addi(instru, beforeg [4]int) [4]int {
    beforeg[instru[3]] = beforeg[instru[1]] + instru[2]
    return beforeg
}

func day16Run(isTest bool) {
    arrayFunc := [16]func([4]int, [4]int) [4]int{addr, addi}
    // 使用 arrayFunc
}

如果你的函数具有不同的签名,可以使用切片并在需要时进行追加,但在调用函数时要小心:
https://stackoverflow.com/questions/37314365/golang-how-do-you-create-a-slice-of-functions-with-different-signatures

英文:

If you use more complexes functions you do this :

func addr(instru, beforeg [4]int) [4]int {
	beforeg[instru[3]] = beforeg[instru[1]] + beforeg[instru[2]]
	return beforeg
}

func addi(instru, beforeg [4]int) [4]int {
	beforeg[instru[3]] = beforeg[instru[1]] + instru[2]
	return beforeg
}

func day16Run(isTest bool) {
	arrayFunc:= [16]func([4]int, [4]int) [4]int{addr, addi}
    // use arrayFunc
}

And if your functions have differnt signatures, use a slice and append as you go, but be careful when calling the functions :
https://stackoverflow.com/questions/37314365/golang-how-do-you-create-a-slice-of-functions-with-different-signatures

huangapple
  • 本文由 发表于 2016年2月26日 17:58:51
  • 转载请务必保留本文链接:https://go.coder-hub.com/35648561.html
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