英文:
In golang: Prevent child processes to receive signals from calling process
问题
给定以下代码:
package main
import (
"os"
"fmt"
"os/exec"
"os/signal"
"syscall"
)
const NUMBER_OF_PEASANTS = 3
func createPeasants() map[string]*exec.Cmd {
peasants := map[string]*exec.Cmd{}
for i := 0; i < NUMBER_OF_PEASANTS; i++ {
name := fmt.Sprintf("peasant#%d", i + 1)
fmt.Printf("[master] Start %s...\n", name)
cmd := exec.Command(os.Args[0], name)
cmd.Stderr = os.Stderr
cmd.Stdin = os.Stdin
cmd.Stdout = os.Stdout
if err := cmd.Start(); err != nil {
panic(err)
}
peasants[name] = cmd
}
return peasants
}
func masterWaitForSignal(c chan os.Signal) {
for true {
s := <-c
fmt.Printf("[master] Got signal %v but still running...\n", s)
}
}
func peasantWaitForSignal(name string, c chan os.Signal) {
s := <-c
fmt.Printf("[%s] Got signal %v and will exit not with code 66\n", name, s)
os.Exit(66)
}
func waitForPeasants(peasants map[string]*exec.Cmd) {
for name, peasant := range peasants {
if err := peasant.Wait(); err != nil {
if exitError, ok := err.(*exec.ExitError); ok {
waitStatus := exitError.Sys().(syscall.WaitStatus)
fmt.Printf("[master] %s ended with exit code %d.\n", name, waitStatus.ExitStatus())
} else {
panic(err)
}
}
}
}
func actAsMaster() {
c := make(chan os.Signal, 1)
signal.Notify(c, os.Interrupt)
peasants := createPeasants()
fmt.Printf("[master] Started.\n")
go masterWaitForSignal(c)
waitForPeasants(peasants)
fmt.Printf("[master] Done.\n")
}
func actAsPeasant(name string) {
c := make(chan os.Signal, 1)
signal.Notify(c, os.Interrupt)
fmt.Printf("[%s] Started.\n", name)
peasantWaitForSignal(name, c)
fmt.Printf("[%s] Done.\n", name)
}
func main() {
if len(os.Args) > 1 {
actAsPeasant(os.Args[1])
} else {
actAsMaster()
}
}
当我运行这段代码并在运行时按下[Ctrl]+[C]时,会产生以下输出:
$ go run signaldemo.go
[master] Start peasant#1...
[master] Start peasant#2...
[master] Start peasant#3...
[peasant#1] Started.
[master] Started.
[peasant#2] Started.
[peasant#3] Started.
^C[peasant#2] Got signal interrupt and will exit not with code 66
[peasant#1] Got signal interrupt and will exit not with code 66
[master] Got signal interrupt but still running...
[master] peasant#1 ended with exit code 66.
[master] peasant#2 ended with exit code 66.
[peasant#3] Got signal interrupt and will exit not with code 66
[master] peasant#3 ended with exit code 66.
[master] Done.
我如何防止子进程接收到中断信号?但我不想重写子进程。需要更改调用进程。
英文:
Given is the following code:
package main
import (
"os"
"fmt"
"os/exec"
"os/signal"
"syscall"
)
const NUMBER_OF_PEASANTS = 3
func createPeasants() map[string]*exec.Cmd {
peasants := map[string]*exec.Cmd{}
for i := 0; i < NUMBER_OF_PEASANTS; i++ {
name := fmt.Sprintf("peasant#%d", i + 1)
fmt.Printf("[master] Start %s...\n", name)
cmd := exec.Command(os.Args[0], name)
cmd.Stderr = os.Stderr
cmd.Stdin = os.Stdin
cmd.Stdout = os.Stdout
if err := cmd.Start(); err != nil {
panic(err)
}
peasants[name] = cmd
}
return peasants
}
func masterWaitForSignal(c chan os.Signal) {
for true {
s := <-c
fmt.Printf("[master] Got signal %v but still running...\n", s)
}
}
func peasantWaitForSignal(name string, c chan os.Signal) {
s := <-c
fmt.Printf("[%s] Got signal %v and will exit not with code 66\n", name, s)
os.Exit(66)
}
func waitForPeasants(peasants map[string]*exec.Cmd) {
for name, peasant := range peasants {
if err := peasant.Wait(); err != nil {
if exitError, ok := err.(*exec.ExitError); ok {
waitStatus := exitError.Sys().(syscall.WaitStatus)
fmt.Printf("[master] %s ended with exit code %d.\n", name, waitStatus.ExitStatus())
} else {
panic(err)
}
}
}
}
func actAsMaster() {
c := make(chan os.Signal, 1)
signal.Notify(c, os.Interrupt)
peasants := createPeasants()
fmt.Printf("[master] Started.\n")
go masterWaitForSignal(c)
waitForPeasants(peasants)
fmt.Printf("[master] Done.\n")
}
func actAsPeasant(name string) {
c := make(chan os.Signal, 1)
signal.Notify(c, os.Interrupt)
fmt.Printf("[%s] Started.\n", name)
peasantWaitForSignal(name, c)
fmt.Printf("[%s] Done.\n", name)
}
func main() {
if len(os.Args) > 1 {
actAsPeasant(os.Args[1])
} else {
actAsMaster()
}
}
When I run the code and hit [Ctrl]+[C] (while it runs) the following output it produced:
$ go run signaldemo.go
[master] Start peasant#1...
[master] Start peasant#2...
[master] Start peasant#3...
[peasant#1] Started.
[master] Started.
[peasant#2] Started.
[peasant#3] Started.
^C[peasant#2] Got signal interrupt and will exit not with code 66
[peasant#1] Got signal interrupt and will exit not with code 66
[master] Got signal interrupt but still running...
[master] peasant#1 ended with exit code 66.
[master] peasant#2 ended with exit code 66.
[peasant#3] Got signal interrupt and will exit not with code 66
[master] peasant#3 ended with exit code 66.
[master] Done.
How can I prevent that the children receives the Interrupt signal? But I do not want to rewrite the children. A change in the calling process is required.
答案1
得分: 11
子进程默认在同一进程组中启动,当你按下 ctrl+c
时,你的 shell 会向所有进程发送信号,试图在中断程序时清理它们。
子进程不会接收到直接发送给父进程的信号。
如果你想阻止 ctrl+c
的行为,你可以在启动进程之前,使用 syscall.SysProcAttr
中的 Setpgid
和 Pgid
字段,强制子进程在自己的进程组中启动。
cmd.SysProcAttr = &syscall.SysProcAttr{
Setpgid: true,
Pgid: 0,
}
英文:
The child processes are starting in the same process group by default, and your shell is sending the signal to all the processes at once when you press ctrl+c
. This is the default behavior of the shell to try and clean up when you interrupt a program.
The child processes won't receive signals sent directly to the parent.
If you want to prevent the ctrl+c
behavior, you can force the child processes to start in their own process groups with with the Setpgid
and Pgid
fields in syscall.SysProcAttr
before starting the processes.
cmd.SysProcAttr = &syscall.SysProcAttr{
Setpgid: true,
Pgid: 0,
}
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库,让每个人都能够通过互相帮助和分享经验来进步。
评论