go struct JSON解码始终返回空的结果 &{}。

huangapple go评论83阅读模式
英文:

go struct JSON decode always empty return &{}

问题

在我的处理程序中,我可能做错了什么?

type Patient struct {
    FirstName string
    LastName  string
}

func createHandler(w http.ResponseWriter, r *http.Request) {

    r.ParseForm()
    p := new(Patient)
    err := json.NewDecoder(r.Body).Decode(&p)

    if err != nil && err != io.EOF {
        log.Fatal(err)
    }

    log.Print(p)
}

我总是从 curl -X POST $PATH -d '{"firstName": "Julian"}' 得到以下输出:

2016/01/23 17:33:50 &{  }

编辑

我添加了 fmt.Println(r) 并得到以下输出:

2016/01/23 18:33:22 &{POST /patients/ HTTP/1.1 1 1 map[Accept:[*/*] Content-Type:[application/json] User-Agent:[curl/7.46.0]] 0x9b2820 0 [] false localhost:8081 map[] map[] <nil> map[] [::1]:35394 /patients/ <nil> <nil>}

在调试了前一行之后,我意识到这是 gorilla 工具包的子路由问题。

英文:

What I can be doing wrong in my handler?

type Patient struct {
    FirstName string
    LastName  string
}


func createHandler(w http.ResponseWriter, r *http.Request) {

	r.ParseForm()
	p := new(Patient)
	err := json.NewDecoder(r.Body).Decode(&amp;p)

	if err != nil &amp;&amp; err != io.EOF {
		log.Fatal(err)
	}

	log.Print(p)
}

I always get from curl -X POST $PATH -d &#39;{&quot;firstName&quot;: &quot;Julian&quot;}&#39;

2016/01/23 17:33:50 &amp;{  }

Edit

I've added fmt.Println(r) and got this

2016/01/23 18:33:22 &amp;{POST /patients/ HTTP/1.1 1 1 map[Accept:[*/*] Content-Type:[application/json] User-Agent:[curl/7.46.0]] 0x9b2820 0 [] false localhost:8081 map[] map[] &lt;nil&gt; map[] [::1]:35394 /patients/ &lt;nil&gt; &lt;nil&gt;}

after debug the previous line I realized it's a problem with the subrouter of gorilla toolkit

答案1

得分: 1

两件事情:

由于您使用的是JSON库的约定,所以您的表单数据应该是FirstName而不是firstName。如果您真的想使用firstName,您需要在字段上添加这个结构标签:json:"firstName"

接下来,您不再需要在&amp;p中放置&amp;,因为new(Patient)已经返回一个指针。只需放置p即可。

尽管个人而言,我会直接使用p := Patient{},这样我就知道它不是一个指针,并在解码器中使用&amp;p

英文:

Two things:

Since you're using the JSON lib convention, then your post form data should be FirstName and not firstName. If you really wanted to use firstName, you need to add this struct tag to the field: json:&quot;firstName&quot;.

Next, you don't need to put &amp; in &amp;p anymore because new(Patient) already returns a pointer. Just put p.

Although personally, I'd just do p := Patient{} just so I know it's not a pointer and use &amp;p in the decoder.

答案2

得分: 0

你需要移除r.ParseForm。你可以在这里阅读更多信息:

https://golang.org/pkg/net/http/#Request.ParseForm

>对于POST或PUT请求,它还会解析请求体

因此,在调用ParseForm之后,你的请求体将为空,并且你将收到一个空的结构体。

英文:

You have to remove the r.ParseForm. You can read here

https://golang.org/pkg/net/http/#Request.ParseForm

>For POST or PUT requests, it also parses the request body

So your request body will be empty after the call of ParseForm and you will receive an empty struct.

huangapple
  • 本文由 发表于 2016年1月24日 06:35:27
  • 转载请务必保留本文链接:https://go.coder-hub.com/34969777.html
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