英文:
println turning up as empty string in go
问题
所以我写了这个小的Go程序，它给图灵机提供指令，并打印其中选定的单元格：
package main
import "fmt"
import s "strings"
func main() {
fmt.Println(processturing("> > > + + + . ."));
}
func processturing(arguments string) string{
result := ""
dial := 0
cells := make([]int, 30000)
commands := splitstr(arguments, " ")
for i := 0;i<len(commands);i++ {
switch commands[i] {
case ">":
dial += 1
case "<":
dial -= 1
case "+":
cells[dial] += 1
case "-":
cells[dial] -= 1
case ".":
result += string(cells[dial]) + " "
}
}
return result
}
//splits strings be a delimeter
func splitstr(input, delim string) []string{
return s.Split(input, delim)
}
问题是，当运行这个程序时，控制台没有显示任何内容。它什么都没有显示。我该如何使其能够将我的函数的结果作为字符串打印出来？
英文:
So I wrote this small go program, that gives instructions to a turing machine, and prints selected cells from it:
package main
import "fmt"
import s "strings"
func main() {
fmt.Println(processturing("> > > + + + . ."));
}
func processturing(arguments string) string{
result := ""
dial := 0
cells := make([]int, 30000)
commands := splitstr(arguments, " ")
for i := 0;i<len(commands);i++ {
switch commands[i] {
case ">":
dial += 1
case "<":
dial -= 1
case "+":
cells[dial] += 1
case "-":
cells[dial] -= 1
case ".":
result += string(cells[dial]) + " "
}
}
return result
}
//splits strings be a delimeter
func splitstr(input, delim string) []string{
return s.Split(input, delim)
}
Problem is, when this is run, the console doesn't display anything. It just displays nothing. How do I make this work to fmt.println the resulting string from my function?
答案1
得分: 6
表达式string(cells[dial])会产生整数值cells[dial]的UTF-8表示。打印带引号的字符串输出以查看发生了什么：
fmt.Printf("%q\n", processturing(">>>+++..")) // 打印 "\x03 \x03"
我认为你想要整数的十进制表示：
strconv.Itoa(cells[dial])
英文:
The expression
string(cells[dial])
yields the UTF-8 representation of the integer value cells[dial]. Print the quoted string output to see what's going on:
fmt.Printf("%q\n", processturing("> > > + + + . .")) // prints "\x03 \x03 "
I think you want the decimal representation of the integer:
strconv.Itoa(cells[dial])
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