Can I make the index int64 in golang's for-range iteration?

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英文:

Can I make the index int64 in golang's for-range iteration?

问题

根据规范for idx, val range a_slice语句中的idx返回的是一个integer类型。由于可以创建大尺寸的切片(slice),是否有办法将idx更改为int64类型?

谢谢。

英文:

According to the spec the

for idx, val range a_slice 

statement returns idx as an integer.

Since creating a large size slice is possible, is there a way to chance idx to int64?

Thank you.

答案1

得分: 12

不,如果你在使用“for”语句和“range”子句时,规范指定索引类型为int

范围表达式                          第一个值          第二个值

数组或切片  a  [n]E, *[n]E, 或 []E    索引    i  int    a[i]       E
字符串          s  字符串类型            索引    i  int    见下文  rune
映射             m  map[K]V                键      k  K      m[k]       V
通道         c  chan E, <-chan E       元素  e  E

你无法改变它,也不应该改变它。切片/数组的长度将适应int

无法创建比最大int更大的切片。尝试使用常量表达式创建更大的切片会导致编译时错误:

x := make([]struct{}, 3123456789)

编译时错误:len argument too large in make([]struct {})

注意:int的大小是与具体实现相关的:它可以是32位或64位。这里产生错误的常量表达式是针对32位int的(Go Playground使用32位int).

如果长度是运行时表达式,会引发恐慌:

i := uint(3123456789)
y := make([]struct{}, i)

运行时错误:panic: runtime error: makeslice: len out of range

数组类型的长度也必须适应int规范:数组类型

> 长度是数组类型的一部分;它必须评估为一个非负的常量,可以由int类型的值表示。

尝试使用更大的长度会导致编译时错误:

var x [3123456789]struct{}
type t1 [3123456789]byte
type t2 [3123456789]struct{}

所有的编译时错误:array bound is too large

英文:

No, the spec specifies the type of index to be int if you use a "for" statement with a "range" clause:

Range expression                          1st value          2nd value

array or slice  a  [n]E, *[n]E, or []E    index    i  int    a[i]       E
string          s  string type            index    i  int    see below  rune
map             m  map[K]V                key      k  K      m[k]       V
channel         c  chan E, &lt;-chan E       element  e  E

Nothing you can do about it, and nothing you should do about it. The length of the slice/array will fit into int.

It is not possible to make a slice bigger than max int. Attempting to make a larger slice with a constant expression is a compile-time error:

x := make([]struct{}, 3123456789)

Compile-time error: len argument too large in make([]struct {})

Note: size of int is implementation-specific: it is either 32-bit or 64-bit. The constant expressions here to produce the errors are for 32-bit ints (the Go Playground uses 32-bit ints).

If length is a runtime expression, it panics:

i := uint(3123456789)
y := make([]struct{}, i)

Runtime error: panic: runtime error: makeslice: len out of range

And length of array types must also fit into int: Spec: Array types:

> The length is part of the array's type; it must evaluate to a non-negative constant representable by a value of type int.

Attempting to use a larger length is a compile-time error:

var x [3123456789]struct{}
type t1 [3123456789]byte
type t2 [3123456789]struct{}

All compile-time error: array bound is too large

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  • 本文由 发表于 2016年1月15日 20:32:15
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