英文:
How to get (and ignore) a value from Go channel
问题
我在select语句中有以下代码。finish的类型是bool。实际上，我并不关心它的值，只要我能接收到任何东西就可以了。然而，Go会给我一个未使用的变量错误。我该如何解决这个问题？
case finish := <- termSig:
我目前的解决方法是使用Println(finish)。
我尝试过：
case _ := <- termSig:
但这也不起作用。
英文:
I have the following code in a select statement. finish is of type bool. Actually, I don't even care of the value as long as I just receive anything. However, Go gives me an unused variable error. How can I get around it?
case finish := <- termSig:
My current workaround is to Println(finish).
I had tried:-
case _ := <- termSig:
but that doesn't work either.
答案1
得分: 7
只需省略变量和:=：
case <-termSig:
英文:
Just omit the variable and the :=:
case <-termSig:
答案2
得分: 2
如在Go Tour中所示，当引入select时，你可以有一个不初始化新变量的情况。
func fibonacci(c, quit chan int) {
x, y := 0, 1
for {
select {
case c <- x:
x, y = y, x+y
case <-quit: // 看起来正是你的用例
fmt.Println("quit")
return
}
}
}
英文:
As is shown in the Go Tour when select is introduced, you can have a case that doesn't initialize a new variable.
func fibonacci(c, quit chan int) {
x, y := 0, 1
for {
select {
case c <- x:
x, y = y, x+y
case <-quit: // looks like exactly your use case
fmt.Println("quit")
return
}
}
}
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