英文:
Does time.Sleep() yield to other goroutines?
问题
在Go语言中，调用time.Sleep()会让出给其他的goroutine吗？我有一种感觉它会，但在其他的答案中（例如：https://stackoverflow.com/questions/10095751/understanding-goroutines），time.Sleep并没有被明确列为调度点。
英文:
In Go, does a call to time.Sleep() yield to other goroutines? I have a feeling it does, but in other answers (eg: https://stackoverflow.com/questions/10095751/understanding-goroutines) time.Sleep is not explicitly listed as a scheduling point.
答案1
得分: 6
是的。请参阅调度器中的抢占。
在之前的版本中，一个无限循环的 goroutine 可能会使同一线程上的其他 goroutine 饿死，当 GOMAXPROCS 只提供一个用户线程时，这是一个严重的问题。在 Go 1.2 中，这个问题在一定程度上得到了解决：调度器在进入函数时会偶尔被调用。这意味着任何包含（非内联）函数调用的循环都可以被抢占，从而允许同一线程上的其他 goroutine 运行。
以下设计文档也是了解调度器更多信息的好资源：
英文:
Yes. See Pre-emption in the scheduler.
> In prior releases, a goroutine that was looping forever could starve out other goroutines on the same thread, a serious problem when GOMAXPROCS provided only one user thread. In Go 1.2, this is partially addressed: The scheduler is invoked occasionally upon entry to a function. This means that any loop that includes a (non-inlined) function call can be pre-empted, allowing other goroutines to run on the same thread.
Following design docs are also good reads to learn more about scheduler:
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