英文:
Go parse string to time
问题
我有以下字符串：
Sun, 03 Jan 2016 10:00:07 CET
我想将其解析为时间，但似乎无法弄清楚如何编写格式。
这是我目前的代码：
layout := "Mon, 01 Jan 03:04:05"
t, _ := time.Parse(layout, "Sun, 03 Jan 2016 10:00:07 CET")
fmt.Println(t)
我得到的输出是：
0001-01-01 00:00:00 +0000 UTC
英文:
I've got the following string:
Sun, 03 Jan 2016 10:00:07 CET
Id like to parse it into time, but cannot seem to figure out how to write the format.
This is what I've got so far:
layout := "Mon, 01 Jan 03:04:05"
t, _ := time.Parse(layout, "Sun, 03 Jan 2016 10:00:07 CET")
fmt.Println(t)
Output I get is:
0001-01-01 00:00:00 +0000 UTC
答案1
得分: 3
首先：你正在默默地忽略time.Parse返回的错误作为第二个返回值。我建议适当地处理这个错误。
其次，让我们来看一下time.Parse的文档：
Parse函数解析一个格式化的字符串并返回它表示的时间值。布局定义了格式，通过展示如果Mon Jan 2 15:04:05 -0700 MST 2006是值的话，它将如何被解释；它作为输入格式的示例。然后，相同的解释将被应用到输入字符串上。
time.Parse函数期望它的layout参数表示一个固定的示例日期。所以，为了解析日期Sun, 03 Jan 2016 10:00:07 CET，适当的示例布局字符串应该是Mon, 02 Jan 2006 15:04:05 MST：
layout := "Mon, 02 Jan 2006 15:04:05 MST"
t, err := time.Parse(layout, "Sun, 03 Jan 2016 10:00:07 CET")
if err != nil {
// 适当处理错误！
}
fmt.Println(t)
英文:
First of all: You're silently ignoring the error this is returned as second return value of time.Parse. I'd suggest handling the error appropriately, instead.
Secondly, let's have a look at the documentation of time.Parse:
>Parse parses a formatted string and returns the time value it represents. The layout defines the format by showing how the reference time, defined to be Mon Jan 2 15:04:05 -0700 MST 2006 would be interpreted if it were the value; it serves as an example of the input format. The same interpretation will then be made to the input string.
The time.Parse function expects its layout parameter to represent a fixed example date. So, in order to parse the date Sun, 03 Jan 2016 10:00:07 CET, the appropriate example layout string should be Mon, 02 Jan 2006 15:04:05 MST:
layout := "Mon, 02 Jan 2006 15:04:05 MST"
t, err := time.Parse(layout, "Sun, 03 Jan 2016 10:00:07 CET")
if err != nil {
// handle the error somehow!
}
fmt.Println(t)
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