英文:
How to access map values in GO?
问题
你好！以下是代码的翻译：
如何访问以下代码中的映射值？代码片段是自动生成的，所以我无法修改它。我尝试了OpType_name[OpType_UNKNOWN]，但是我得到了来自golang编译器的错误。
type OpType int32
const (
OpType_UNKNOWN OpType = 0
OpType_CREATE OpType = 1
OpType_DELETE OpType = 3
)
var OpType_name = map[int32]string{
0: "UNKNOWN",
1: "CREATE",
2: "DELETE",
}
var OpType_value = map[string]int32{
"UNKNOWN": 0,
"CREATE": 1,
"DELETE": 2,
}
错误信息：
cannot use int(api.OpType_UNKNOWN) (type int) as type int32 in map index
请注意，错误信息中提到的int(api.OpType_UNKNOWN)是将OpType_UNKNOWN转换为int类型，而不是int32类型。你可以尝试将其更改为int32(OpType_UNKNOWN)来解决此错误。
英文:
How do I access the map value for the following code? The code snippet is auto generated, so I can't modify it. I have tried OpType_name[OpType_UNKNOWN] but I am getting error from the golang compiler.
type OpType int32
const (
OpType_UNKNOWN OpType = 0
OpType_CREATE OpType = 1
OpType_DELETE OpType = 3
)
var OpType_name = map[int32]string{
0: "UNKNOWN",
1: "CREATE",
2: "DELETE",
}
var OpType_value = map[string]int32{
"UNKNOWN": 0,
"CREATE": 1,
"DELETE": 2,
}
Error:
cannot use int(api.OpType_UNKNOWN) (type int) as type int32 in map index
答案1
得分: 7
Go对类型要求非常严格。你的映射（maps）中所有的键都是int32类型的，而你试图使用OpType类型的值来访问它们。OpType是int32类型并不重要。
你可以将OpType转换为int32类型，这样就可以正常工作了。
func main() {
fmt.Println(OpType_name[int32(OpType_UNKNOWN)])
}
@nos的评论是一个不错的方法，这可能是你在这种情况下想要的。
https://play.golang.org/p/dum5GiB3zS
英文:
Go is very strict on types. Your maps all have keys with typ int32 and you are trying to access them using a value of type OpType. It doesn't matter that OpType is an int32.
You can cast your OpType to int32 and make it work
func main() {
fmt.Println(OpType_name[int32(OpType_UNKNOWN)])
}
The comment from @nos is a good way to go, it's probably what you want in this case.
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