英文:
Unmarshal json into struct: cannot unmarshal array into Go value
问题
我有一个通过REST提供属性的服务。现在我想将响应体解组为一个属性结构体。请参考这个playground示例：点击。当我只有一个属性时，我可以轻松地将其解组为一个Property。然而，实际服务器返回的响应与之有所不同。我想要解组的实际响应如下：
[{"key": "blabla","secret": false,"type": "string","value": "hereisthevalue"},{"key": "yepyepakey","secret": true,"type": "string","value": "dummy"}]
不幸的是，我不知道如何解组这个响应。有人可以指点我正确的方向吗？
英文:
I have a service which provides me properties through REST. Now I want to unmarshal the body into a properties struct. Please see this playground example: click. When I have only one property, I can easily unmarshal it into a Property. However the ACTUAL response from the server is somehow difference. The actual response I want to unmarshal is this:
[{"key": "blabla","secret": false,"type": "string","value": "hereisthevalue"},{"key": "yepyepakey","secret": true,"type": "string","value": "dummy"}]
Unfortunately I don't know how to unmarshal this. Can someone please point me in the right direction?
答案1
得分: 19
你需要将其解组为 Property 的切片：
http://play.golang.org/p/eRgjfBHypH
var props []Propertyer := json.Unmarshal(resp, &props)if er != nil {panic(er)} else {fmt.Println(props)}
英文:
You need to unmarshal into a slice of Property:
http://play.golang.org/p/eRgjfBHypH
var props []Propertyer := json.Unmarshal(resp, &props)if er != nil {panic(er)} else {fmt.Println(props)}
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论