使用http.ServeFile更改HTTP代码

huangapple go评论91阅读模式
英文:

Changing HTTP code with http.ServeFile

问题

我正在使用Go编写一个服务器,目前正在实现错误页面(404、500等)。我有一些可以用于这些错误的文件,但是如果我使用http.ServeFile,那么我得到的是HTTP代码200,而不是适当的代码。

有没有办法更改状态码,或者我需要为这种情况重写http.ServeFile

英文:

I'm writing a server in Go, and I'm currently implementing error pages (404, 500, etc.) I have files which can be served for these errors, but if I use http.ServeFile then I get HTTP code 200 instead of the appropriate code.

Is there a way to change the status code, or do I need to rewrite http.ServeFile for this use case?

答案1

得分: 3

从阅读源代码中,我没有看到任何改变状态码的方法(除非方法失败,这意味着您将无法获取错误页面)。我认为如果文件被提供,则暗示着它是一个HTTP 200,这并不完全不合理。

我建议将错误页面文件读入字符串,然后使用这个方法:https://golang.org/pkg/net/http/#Error

编辑:实际上,这可能对您来说还不够具体。它希望将错误消息作为纯文本,所以我建议的可能是一种误用。在这种情况下,您将无法使用任何有用的抽象来实现您想要的功能。

回应评论,我个人更喜欢以下方式:

func main() {
    mux := http.NewServeMux()
    mux.HandleFunc("/sendstrailers", func(w http.ResponseWriter, req *http.Request) {
        resp := &http.Response{
            StatusCode: 404,
        }
        resp.Write(w)
    })
}

但是如果您喜欢的话,您也可以使用w.WriteHeader(http.StatusForbidden)或其他任何方法。选择更适合您需求的方式。根据我的经验,我更喜欢在与mux不同的作用域中准备响应对象,因此我更喜欢上面的代码片段(它比让辅助方法返回非结构化数据然后写入响应写入器更有意义)。

英文:

From reading the source I don't see any way to change the status code (other than the method failing which means you won't get your error page served). I think it's implied that if the files is served then it was an HTTP 200 which isn't entirely unreasonable.

I recommend reading the error page file into a string then using this method; https://golang.org/pkg/net/http/#Error

EDIT: That may actually not be specific enough for you even. It wants the error message as plain text so what I suggested is likely a misuse. In which case you're left with no useful abstractions to do what you want.

In response to comment, my personal preference would be something more along the line of;

func main() {
	mux := http.NewServeMux()
	mux.HandleFunc("/sendstrailers", func(w http.ResponseWriter, req *http.Request) {
		resp := &http.Response{
			StatusCode: 404,
		}
		resp.Write(w)
	})
}

but you could also just use w.WriteHeader(http.StatusForbidden) or whatever if that's your preference. Whatever better suites you needs. My experience would be with preparing response object in a scope different than that of the mux so for that reason I think I prefer the bit above (it makes more sense than having helper methods return unstructured data you then write in to the responsewriter).

huangapple
  • 本文由 发表于 2015年12月4日 02:19:26
  • 转载请务必保留本文链接:https://go.coder-hub.com/34073377.html
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