英文:
Removing a string from a slice in Go
问题
我可以帮你翻译代码部分。以下是翻译好的代码：
我有一个字符串切片，我想要移除其中的一个特定字符串。
strings := []string
strings = append(strings, "one")
strings = append(strings, "two")
strings = append(strings, "three")
现在，我该如何从 strings 中移除字符串 "two"？
英文:
I have a slice of strings, and I want to remove a specific one.
strings := []string
strings = append(strings, "one")
strings = append(strings, "two")
strings = append(strings, "three")
Now how can I remove the string "two" from strings?
答案1
得分: 24
找到你想要删除的元素，并像删除任何其他切片中的元素一样将其删除。
找到它是一个线性搜索。删除可以使用以下其中一种切片技巧来完成：
a = append(a[:i], a[i+1:]...)
// 或者
a = a[:i+copy(a[i:], a[i+1:])]
以下是完整的解决方案（在Go Playground上尝试）：
s := []string{"one", "two", "three"}
// 查找并删除"two"
for i, v := range s {
if v == "two" {
s = append(s[:i], s[i+1:]...)
break
}
}
fmt.Println(s) // 输出 [one three]
如果你想将其封装成一个函数：
func remove(s []string, r string) []string {
for i, v := range s {
if v == r {
return append(s[:i], s[i+1:]...)
}
}
return s
}
使用它：
s := []string{"one", "two", "three"}
s = remove(s, "two")
fmt.Println(s) // 输出 [one three]
英文:
Find the element you want to remove and remove it like you would any element from any other slice.
Finding it is a linear search. Removing is one of the following slice tricks:
a = append(a[:i], a[i+1:]...)
// or
a = a[:i+copy(a[i:], a[i+1:])]
Here is the complete solution (try it on the Go Playground):
s := []string{"one", "two", "three"}
// Find and remove "two"
for i, v := range s {
if v == "two" {
s = append(s[:i], s[i+1:]...)
break
}
}
fmt.Println(s) // Prints [one three]
If you want to wrap it into a function:
func remove(s []string, r string) []string {
for i, v := range s {
if v == r {
return append(s[:i], s[i+1:]...)
}
}
return s
}
Using it:
s := []string{"one", "two", "three"}
s = remove(s, "two")
fmt.Println(s) // Prints [one three]
答案2
得分: 1
这是一个用于删除特定索引处元素的函数：
package main
import "fmt"
import "errors"
func main() {
strings := []string{}
strings = append(strings, "one")
strings = append(strings, "two")
strings = append(strings, "three")
strings, err := remove(strings, 1)
if err != nil {
fmt.Println("Something went wrong: ", err)
} else {
fmt.Println(strings)
}
}
func remove(s []string, index int) ([]string, error) {
if index >= len(s) {
return nil, errors.New("Out of Range Error")
}
return append(s[:index], s[index+1:]...), nil
}
在Go Playground上尝试一下。
英文:
Here is a function to remove the element at a particular index:
package main
import "fmt"
import "errors"
func main() {
strings := []string{}
strings = append(strings, "one")
strings = append(strings, "two")
strings = append(strings, "three")
strings, err := remove(strings, 1)
if err != nil {
fmt.Println("Something went wrong : ", err)
} else {
fmt.Println(strings)
}
}
func remove(s []string, index int) ([]string, error) {
if index >= len(s) {
return nil, errors.New("Out of Range Error")
}
return append(s[:index], s[index+1:]...), nil
}
Try it on Go Playground
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