Go xml unmarshal doesn't work unless I remove preceding xml version="1.0" encoding="ISO-8859-1"

huangapple
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英文:

Go xml unmarshal doesn't work unless I remove preceding xml version="1.0" encoding="ISO-8859-1"

问题

我已经花了几个小时来弄清楚这个问题，但我不明白为什么它只返回一个空字符串。如果我将响应体剪切并粘贴到一个变量中，并删除 "?xml version="1.0" encoding="ISO-8859-1" ?"，它就可以正常工作。

  1. package main
  3. import (
  4. 	"encoding/xml"
  5. 	"fmt"
  6. 	"io/ioutil"
  7. 	"net/http"
  8. )
  10. type entry struct {
  11. 	XMLName  xml.Name `xml:"entry"`
  12. 	Title    string   `xml:"title"`
  13. 	Link     string   `xml:"link"`
  14. 	Summary  string   `xml:"summary"`
  15. 	Updated  string   `xml:"updated"`
  16. 	Catagory string   `xml:"catagory"`
  17. 	ID       string   `xml:"id"`
  18. }
  20. type Feed struct {
  21. 	XMLName xml.Name `xml:"feed"`
  22. 	Title   string   `xml:"title"`
  23. 	Entry   []entry  `xml:"entry"`
  24. }
  26. func main() {
  27. 	resp, err := http.Get("https://www.sec.gov/cgi-bin/browse-edgar?action=getcurrent&type=4&company=&dateb=&owner=include&start=0&count=2&output=atom")
  28. 	if err != nil {
  29. 		fmt.Println("Get sec main xml error: %s", err)
  30. 	}
  31. 	defer resp.Body.Close()
  32. 	body, err := ioutil.ReadAll(resp.Body)
  33. 	//fmt.Println(string(body))
  34. 	var feedData Feed
  35. 	xml.Unmarshal(body, &feedData)
  37. 	fmt.Println(feedData.Title)
  39. 	for _, entry := range feedData.Entry {
  40. 		fmt.Println(entry.ID)
  41. 	}
  42. }

有人能看出我犯了什么错误吗？感谢任何帮助。

英文:

I've spent a few hours trying to figure this out but I cannot see why this wont return anything but an empty string. If I cut and paste the response body to a variable and remove the ?xml version="1.0" encoding="ISO-8859-1" ? it works fine.

  1. package main
  3. import (
  4. 	"encoding/xml"
  5. 	"fmt"
  6. 	"io/ioutil"
  7. 	"net/http"
  8. )
  10. type entry struct {
  11. 	XMLName  xml.Name `xml:"entry"`
  12. 	Title    string   `xml:"title"`
  13. 	Link     string   `xml:"link"`
  14. 	Summary  string   `xml:"summary"`
  15. 	Updated  string   `xml:"updated"`
  16. 	Catagory string   `xml:"catagory"`
  17. 	ID       string   `xml:"id"`
  18. }
  20. type Feed struct {
  21. 	XMLName xml.Name `xml:"feed"`
  22. 	Title   string   `xml:"title"`
  23. 	Entry   []entry  `xml:"entry"`
  24. }
  26. func main() {
  27. 	resp, err := http.Get("https://www.sec.gov/cgi-bin/browse-edgar?action=getcurrent&type=4&company=&dateb=&owner=include&start=0&count=2&output=atom")
  28. 	if err != nil {
  29. 		fmt.Println("Get sec main xml error: %s", err)
  30. 	}
  31. 	defer resp.Body.Close()
  32. 	body, err := ioutil.ReadAll(resp.Body)
  33. 	//fmt.Println(string(body))
  34. 	var feedData Feed
  35. 	xml.Unmarshal(body, &feedData)
  37. 	fmt.Println(feedData.Title)
  39. 	for _, entry := range feedData.Entry {
  40. 		fmt.Println(entry.ID)
  41. 	}
  42. }

Can anyone see where I'm making the mistake? Thanks for any assistance.

答案1

得分: 1

根据codefreak提供的链接，答案是由moraes在“Updated answer for 2015 & beyond”中给出的。
更新的工作代码：

  1. package main
  3. import (
  4. 	"encoding/xml"
  5. 	"fmt"
  6. 	"golang.org/x/net/html/charset"
  7. 	"net/http"
  8. )
  10. type entry struct {
  11. 	XMLName  xml.Name `xml:"entry"`
  12. 	Title    string   `xml:"title"`
  13. 	Link     string   `xml:"link"`
  14. 	Summary  string   `xml:"summary"`
  15. 	Updated  string   `xml:"updated"`
  16. 	Catagory string   `xml:"catagory"`
  17. 	ID       string   `xml:"id"`
  18. }
  20. type Feed struct {
  21. 	XMLName xml.Name `xml:"feed"`
  22. 	Title   string   `xml:"title"`
  23. 	Entry   []entry  `xml:"entry"`
  24. }
  26. func main() {
  27. 	resp, err := http.Get("https://www.sec.gov/cgi-bin/browse-edgar?action=getcurrent&type=4&company=&dateb=&owner=include&start=0&count=2&output=atom")
  28. 	if err != nil {
  29. 		fmt.Println("Get sec main xml error: %s", err)
  30. 	}
  31. 	defer resp.Body.Close()
  32. 	var feedData Feed
  33. 	decoder := xml.NewDecoder(resp.Body)
  34. 	decoder.CharsetReader = charset.NewReaderLabel
  35. 	err = decoder.Decode(&feedData)
  37. 	fmt.Println(feedData.Title)
  39. 	for _, entry := range feedData.Entry {
  40. 		fmt.Println(entry.ID)
  41. 	}
  42. }

谢谢！

英文:

from the link provided by codefreak the answer was by moraes in "Updated answer for 2015 & beyond"
Updated working code:

  1. package main
  3. import (
  4. 	"encoding/xml"
  5. 	"fmt"
  6. 	"golang.org/x/net/html/charset"
  7. 	"net/http"
  8. )
  10. type entry struct {
  11. 	XMLName  xml.Name `xml:"entry"`
  12. 	Title    string   `xml:"title"`
  13. 	Link     string   `xml:"link"`
  14. 	Summary  string   `xml:"summary"`
  15. 	Updated  string   `xml:"updated"`
  16. 	Catagory string   `xml:"catagory"`
  17. 	ID       string   `xml:"id"`
  18. }
  20. type Feed struct {
  21. 	XMLName xml.Name `xml:"feed"`
  22. 	Title   string   `xml:"title"`
  23. 	Entry   []entry  `xml:"entry"`
  24. }
  26. func main() {
  27. 	resp, err := http.Get("https://www.sec.gov/cgi-bin/browse-edgar?action=getcurrent&type=4&company=&dateb=&owner=include&start=0&count=2&output=atom")
  28. 	if err != nil {
  29. 		fmt.Println("Get sec main xml error: %s", err)
  30. 	}
  31. 	defer resp.Body.Close()
  32. 	var feedData Feed
  33. 	decoder := xml.NewDecoder(resp.Body)
  34. 	decoder.CharsetReader = charset.NewReaderLabel
  35. 	err = decoder.Decode(&feedData)
  37. 	fmt.Println(feedData.Title)
  39. 	for _, entry := range feedData.Entry {
  40. 		fmt.Println(entry.ID)
  41. 	}
  42. }

Thank you!

huangapple
  • 本文由 发表于 2015年11月19日 14:59:34
  • 转载请务必保留本文链接：https://go.coder-hub.com/33797182.html
  • go
  • unmarshalling
  • xml
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