英文:
Why doesn't time.Sleep(2) work with go routines?
问题
从这里的go例子中：https://gobyexample.com/goroutines，为什么用time.Sleep(2)替换fmt.Scanln的代码不起作用？
如果你用time.Sleep(2)替换最后三行代码，go例程将不会打印任何内容。
func main() {
f("direct")
go f("goroutine")
go func(msg string) {
fmt.Println(msg)
}("going")
time.Sleep(2)
}
英文:
From the go routine example here: https://gobyexample.com/goroutines, why doesn't replacing the fmt.Scanln code with a time.sleep(2) work?
If you replace the last three lines with time.Sleep(2), the go routines don't print anything.
func main() {
f("direct")
go f("goroutine")
go func(msg string) {
fmt.Println(msg)
}("going")
time.Sleep(2)
}
答案1
得分: 4
time.Sleep 函数接受一个 time.Duration 类型的参数，单位为纳秒。如果你想要秒数，可以使用 time.Sleep(2*time.Second)：
f("direct")
go f("goroutine")
go func(msg string) {
fmt.Println(msg)
}("going")
time.Sleep(2 * time.Second)
Playground: http://play.golang.org/p/lgKSyAW4RO.
但是最好使用通道或 sync 包中的工具进行同步。
英文:
time.Sleep takes time.Duration as an argument, which is in nanoseconds. If you want seconds, use time.Sleep(2*time.Second):
f("direct")
go f("goroutine")
go func(msg string) {
fmt.Println(msg)
}("going")
time.Sleep(2 * time.Second)
Playground: http://play.golang.org/p/lgKSyAW4RO.
But it's always better to use channels or tools from package sync for synchronisation.
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