Golang解析POST请求

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英文:

golang parse POST request

问题

我有一个带有负载的HTTP POST请求

indices=0%2C1%2C2

这是我的Golang后端代码

err := r.ParseForm()
if err != nil {
	http.Error(w, err.Error(), http.StatusInternalServerError)
	return
}
log.Println("r.PostForm", r.PostForm)
log.Println("r.Form", r.Form)

body, err := ioutil.ReadAll(r.Body)
if err != nil {
	http.Error(w, err.Error(), http.StatusInternalServerError)
	return
}
log.Println("r.Body", string(body))

values, err := url.ParseQuery(string(body))
if err != nil {
	http.Error(w, err.Error(), http.StatusInternalServerError)
	return
}
log.Println("indices from body", values.Get("indices"))

输出结果:

r.PostForm map[]
r.Form map[]
r.Body indices=0%2C1%2C2
indices from body 0,1,2

为什么POST请求没有被r.ParseForm()解析,而手动使用url.ParseQuery(string(body))解析可以得到正确的结果?

英文:

I have a HTTP POST request with payload

indices=0%2C1%2C2

Here is my golang backend code

err := r.ParseForm()
if err != nil {
	http.Error(w, err.Error(), http.StatusInternalServerError)
	return
}
log.Println("r.PostForm", r.PostForm)
log.Println("r.Form", r.Form)

body, err := ioutil.ReadAll(r.Body)
if err != nil {
	http.Error(w, err.Error(), http.StatusInternalServerError)
	return
}
log.Println("r.Body", string(body))

values, err := url.ParseQuery(string(body))
if err != nil {
	http.Error(w, err.Error(), http.StatusInternalServerError)
	return
}
log.Println("indices from body", values.Get("indices"))

Output:

r.PostForm map[]
r.Form map[]
r.Body indices=0%2C1%2C2
indices from body 0,1,2

Why is it that the POST request is not parsed by r.ParseForm(), while manaully parsing it with url.ParseQuery(string(body)) gives the correct result?

答案1

得分: 18

问题不在于你的服务器代码,它是正确的,而是你的客户端缺少正确的Content-Type头部信息用于POST表单。只需在你的客户端中设置头部信息为:

Content-Type: application/x-www-form-urlencoded
英文:

The problem is not in your server code which is fine, but simply that your client, whatever it is, is missing the correct Content-Type header for POST forms. Simply set the header to

Content-Type: application/x-www-form-urlencoded

In your client.

答案2

得分: 8

从你的 http.Request 中使用 PostFormValue("params") 获取参数的值。

err := r.ParseForm() 
if err != nil{
       panic(err)
}

params := r.PostFormValue("params") // 使用键获取参数值

请注意,这是一个示例代码片段,用于从 HTTP 请求中获取名为 "params" 的参数值。你可以根据自己的需求进行修改和使用。

英文:

> Get value form your params use PostFormValue("params") from your http.Request

err := r.ParseForm() 
if err != nil{
       panic(err)
}

params := r.PostFormValue("params") // to get params value with key

huangapple
  • 本文由 发表于 2015年10月16日 15:14:31
  • 转载请务必保留本文链接:https://go.coder-hub.com/33164564.html
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