Create array of array literal in Golang

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英文:

Create array of array literal in Golang

问题

如何在Golang中使用切片字面量创建一个int数组的数组?

我尝试了以下两种方式:

test := [][]int{{1,2,3},{1,2,3}}

type Test struct {
   foo [][]int
}

bar := Test{foo: [][]int{{1,2,3}, {1,2,3}}}

这样就可以创建一个int数组的数组了。

英文:

How do I create an array of int arrays in Golang using slice literals?

I've tried

test := [][]int{[1,2,3],[1,2,3]}

and

type Test struct {
   foo [][]int
}

bar := Test{foo: [[1,2,3], [1,2,3]]}

答案1

得分: 50

你几乎做对了,但是你内部数组的语法有点问题,需要使用花括号,像这样:test := [][]int{[]int{1,2,3},[]int{1,2,3}} 或者稍微简洁一些的写法:test := [][]int{{1,2,3},{1,2,3}}

这个表达式被称为“复合字面量”,你可以在这里了解更多信息:https://golang.org/ref/spec#Composite_literals

但是作为一个基本的经验法则,如果你有嵌套的结构,你必须递归地使用这种语法。它非常冗长。

英文:

You almost have the right thing however your syntax for the inner arrays is slightly off, needing curly braces like; test := [][]int{[]int{1,2,3},[]int{1,2,3}} or a slightly more concise version; test := [][]int{{1,2,3},{1,2,3}}

The expression is called a 'composite literal' and you can read more about them here; https://golang.org/ref/spec#Composite_literals

But as a basic rule of thumb, if you have nested structures, you have to use the syntax recursively. It's very verbose.

答案2

得分: 6

在一些其他的语言(Perl、Python、JavaScript)中,[1,2,3] 可能是一个数组字面量,但在 Go 语言中,复合字面量 使用花括号,并且在这里,你必须指定外部切片的类型:

package main

import "fmt"

type T struct{ foo [][]int }

func main() {
    a := [][]int{{1, 2, 3}, {4, 5, 6}}
    b := T{foo: [][]int{{1, 2, 3}, {4, 5, 6}}}
    fmt.Println(a, b)
}

你可以在 Playground 上运行或测试它。

Go 编译器足够聪明,可以推断出 [][]int 的元素是 []int,无需在每个元素上都声明类型。但是,你必须写出外部类型的名称。

英文:

In some other langauges (Perl, Python, JavaScript), [1,2,3] might be an array literal, but in Go, composite literals use braces, and here, you have to specify the type of the outer slice:

package main

import "fmt"

type T struct{ foo [][]int }

func main() {
	a := [][]int{{1, 2, 3}, {4, 5, 6}}
	b := T{foo: [][]int{{1, 2, 3}, {4, 5, 6}}}
	fmt.Println(a, b)
}

You can run or play with that on the Playground.

The Go compiler is just tricky enough to figure out that the elements of an [][]int are []int without you saying so on each element. You do have to write out the outer type's name, though.

答案3

得分: 6

只需将方括号替换为花括号即可。在Go语言中,数组字面量使用花括号进行标识。

test := [][]int{{1,2,3},{1,2,3}}
英文:

Just replace the square brackets with curly braces. In Go, array literals are identified with curly braces.

test := [][]int{{1,2,3},{1,2,3}}

答案4

得分: 1

一个切片字面量的写法是[]type{<value 1>, <value 2>, ... }。一个整数切片可以写作[]int{1,2,3},一个整数切片的切片可以写作[][]int{[]int{1,2,3},[]int{4,5,6}}

groups := [][]int{[]int{1,2,3},[]int{4,5,6}}

for _, group := range groups {
    sum := 0
    for _, num := range group {
        sum += num
    }
    fmt.Printf("数组 %+v 的和为 %d\n", group, sum)
}
英文:

A slice literal is written as []type{&lt;value 1&gt;, &lt;value 2&gt;, ... }. A slice of ints would be []int{1,2,3} and a slice of int slices would be [][]int{[]int{1,2,3},[]int{4,5,6}}.

groups := [][]int{[]int{1,2,3},[]int{4,5,6}}

for _, group := range groups {
	sum := 0
	for _, num := range group {
		sum += num
	}
	fmt.Printf(&quot;The array %+v has a sum of %d\n&quot;, sub, sum)
} 

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  • 本文由 发表于 2015年10月14日 13:00:30
  • 转载请务必保留本文链接:https://go.coder-hub.com/33116941.html
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